If a diagonal beam is 55 feet long that supports a wall that is 33 feet high. How long is the wall?

Mathematics

1 answer:

Musya8 [376]2 years ago

7 0

Answer: The answer is 176 or 7260

Step-by-step explanation: there is 2 sides of the wall that is 55 feet long you need to time it by 2 which will be 110. then there are 2 sides of the wall that is 33 feet high by 2 which equals 66 then add together which will be 176 or if you want to multiply the answers it will be 7260.

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MrRa [10]

Answer:

$\frac{x^2+19x-56}{4x^2-32x}$

Step-by-step explanation:

To add two fractions we need a common denominator. Just by looking at the two, there are no common factors. This means the denominator would be the product of the two: 4x(x-8). In order to obtain this, we multiply the first fraction by (x-8)/(x-8) - 1, and the second by 4x/4x - 1:

$\frac{x+7}{4x} *\frac{x-8}{x-8} +\frac{5}{x-8}*\frac{4x}{4x}$