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Sveta_85 [38]
3 years ago
5

A photo is 4 inches wide. It is placed inside a frame with a border that is x inches wide. The total width of the photo and the

frame is 7 inches. Write an equation to model the situation, then solve the equation to find the width of the border.
Mathematics
1 answer:
Anna [14]3 years ago
5 0
4 + 2x = 7
2x = 7 - 4 = 3
x = 3/2 = 1.5 inches
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Help me solve this question pls
Ganezh [65]
Answer: 15%
Because 3162.50 divided by 2750 is 1.15
1.15 x 100 is 115%
115-100 = 15% increase
7 0
3 years ago
Read 2 more answers
Does anyone know how to do this? Thanks!
Nataly [62]

C. 5

Step-by-step explanation:

The coeff of

{x}^{5}

Is 15.

So by that we can write 3m = 15

m is 5.

8 0
3 years ago
How do you do this? Thanks for your time and effort!
V125BC [204]
Well first you have to simplify the denominators with x, by multiplying the denominator on the left times the top and bottom of the middle, and vice versa to get 10x/(4x^2-4x)-9(2x-2)/(4x^2-4x)=-1/4 and then you combine the fractions on the left to get 2(9-4x)/(4x^2-4x)=-1/4 and then you cross multiply the fractions to get 8(9-4x)=-4x^2+4x and then simplify to get 72-32x=-4x^2+4x and then 4x^2-36x+72=0 which then we can turn into 4(x-6)(x-3)=0 so x is 6 and 3
3 0
4 years ago
Which statement best describes making payments with a debit card?
FromTheMoon [43]
The answer is A.payments are directly deducted from your account
5 0
3 years ago
The function f(x)=125(0.9)x models the population of a species of fly in millions after x years.
SSSSS [86.1K]
A word to the wise:  It's  <span> f(x)=125(0.9)^x,   where ^ represents exponentiation.

In this case the ave. value over the interval [11, 15] is

 125(0.9)^15 - 125(0.9)^11
------------------------------------- = (125/4) [ 0.9^15 - 0.9^11)
               15 - 11                    =  (31.25) [ 0.2059 - 0.3138 ] = a negative result
                                              =  (31.25)(-0.1079) = -3.372  (av. r. of c.
                                                     over the interval [11,15] )

Do the same thing for the time interval [1,5].  Then compare the two rates of change.</span>
6 0
3 years ago
Read 2 more answers
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