Question

What is the expression and value of "six less than the quotient of a number and two, increased by ten" when n = 20?

Answer 1

Answer:

The value is 14

Step-by-step explanation:

six less than (next quotient -6) the quotient of a number and two (n/2), increased by ten (+10) when n = 20.

(n/2)+10-6; n=20

Substitute 20 in for n.

(20/2)+10-6

Divide and subtract.

10+4

Add.

14

Answer 2

Answer:

$\dfrac{n}{2}-6+10,\ \ \textsf{when} \ n = 20, \ \ \textsf{the value is} \ 14$

Step-by-step explanation:

$\dfrac{n}{2}-6+10,\ \ \textsf{when} \ n = 20\\\\\implies \dfrac{20}{2}-6+10\\\\\implies 10-6+10=14$