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navik [9.2K]
2 years ago
13

What is the name given to the

Biology
1 answer:
vlada-n [284]2 years ago
4 0

Answer:

B

Explanation:

the others don't match.

"Oxidative phosphorylation is the final stage of aerobic cellular respiration. There are two substages of oxidative phosphorylation, Electron transport chain and Chemiosmosis. In these stages, energy from NADH and FADH2, which result from the previous stages of cellular respiration, is used to create ATP."

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A scientific model doesnt need to be something physical. It can also be a mathmatical____
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I would go with mathmatical formula because of physics and what not but I'm not completely sure so if you have a different possible answer you think would be better, go with that :)
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4 years ago
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Why is there power in Oxygen?
san4es73 [151]
Because it has reached the stage of a noble gas
8 0
3 years ago
In phylogenetic inference, an evolutionary novelty (or derived character) is referred to as _____.
Tems11 [23]

Solution:

In phylogenetic inference, an evolutionary novelty (or derived character) is referred to as Plesiomorphy

Relating to or denoting the process by which different kinds of living organisms are believed to have developed from earlier forms during the history of the earth.

Thus this is the required answer.


5 0
3 years ago
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Can i have some help on this
Delicious77 [7]

Answer:

Directional selection.

6 0
3 years ago
Hemophilia is Xlinked recessive trait .Consider a cross between a women who is carrier and man who suffers from hemophilia,Which
lozanna [386]

Answer:

II and III

Explanation:

<em>I. All sons of these parents will be a hemophiliac. </em>

<em> II. A son who suffers from hemophilia received the hemophilia allele from his mother. </em>

<em> III. Half of the daughters of this cross are predicted to be hemophiliacs.</em>

Assuming the haemophilia allele is represented by h, the alternate form being H.

A woman that is a carrier will have the genotype X^H X^h.

A man who suffers from haemophilia will have the genotype X^h Y

Crossing both of them:

X^H X^h   x   X^h Y  =  X^H X^h, X^H Y, X^hX^h and X^hY

From the result of the cross, the following can be deduced:

  • Half or 50% of the sons from the couple will be haemophiliacs.
  • Any son that suffers from haemophilia received the allele from the mother.
  • Half or 50% of the daughters from this cross will be hemophiliacs.

Hence, statements II and III are true.

5 0
4 years ago
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