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Nata [24]
3 years ago
8

Radhika’s mother gave her some money to buy Papaya from the market at

Mathematics
1 answer:
amm18123 years ago
4 0

Answer:

p ( x ) = ( x- 6 ) ² - 256

Step-by-step explanation:

1- Add the same value to both sides

2- Add 36 to the expression

3- Add 36 to the left-hand  side

4- Factor the expression

5- Move the constant to the right

6- Calculate

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What is the minimum value for h(x)=x^2−16x+60? Enter your answer in the box.
Dominik [7]
-58.

To get this, first use the equation -b/2a. This will first find the maximum. After you find the maximum, input the answer into the original equation and solve for the minimum.

Hope this helps!
4 0
3 years ago
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In pauls bicycle shop, 40 bicycles are inspected. If 20 needed new tires and 30 needed gear reports, answer the following: a) wh
Arisa [49]
<span>There are three possibilities. 1. Of the 30 bikes that needed gear repairs, 20 also needed tires. 2. Of the 30 bikes that needed gear repairs, 10 also needed tires. 3. Of the 30 bikes that needed gear repairs, between 10 and 20 also needed tires.</span>
7 0
3 years ago
Solve 5x = 2 written a afrction inits simplest form
Elden [556K]

Answer:

x = 2/5

General Formulas and Concepts:

Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Write equation</u>

5x = 2

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Divide both sides by 5:          x = 2/5

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution</em>.

  1. Substitute:                    5(2/5) = 2
  2. Multiply:                        10/5 = 2
  3. Divide:                           2 = 2
4 0
3 years ago
How do you find the HCF of 15t and 6s?
earnstyle [38]

Answer:

HCF=3

Step-by-step explanation:

Factors of 15t= 3*5*t

Factors of 6s= 2*3*s

HCF= Common factors

common factor = 3

HCF=3

4 0
3 years ago
Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3)
vredina [299]

a vertical axis, I assume it means a vertical axis of symmetry, thus it'd be a vertical parabola, like the one in the picture below.

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \qquad \leftarrow vertical\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=0 \end{cases}\implies y=a(x-0)^2+0 \\\\\\ \textit{we also know that } \begin{cases} x=-2\\ y=3 \end{cases}\implies 3=a(-2-0)^2+0\implies 3=4a \\\\\\ \cfrac{3}{4}=a~\hspace{10em}y=\cfrac{3}{4}(x-0)^2+0\implies \boxed{y=\cfrac{3}{4}x^2}

8 0
3 years ago
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