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zheka24 [161]
2 years ago
5

Find the difference by subtracting the second polynomial from the first.

Mathematics
1 answer:
Marysya12 [62]2 years ago
6 0

Answer: a²+2b+2ab

Step-by-step explanation:

(2a²+62+2b+1)-(a²+62-2ab+1)

2a²+62+2b+1 - a²-62+2ab-1

a²+2b+2ab

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Answer:

39ft by 34ft

Step-by-step explanation:

4 and 1/3 is equal (by doing 4*3+1)to 13/3 which is equal (by doing 13/3 *3/3)to 39/9 inches which according to the conversion is equal to 39ft

3 and 7/9 is equal (3*9+7)to 34/9 inches which when converted is 34ft

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At a​ little-known vacation​ spot, taxi fares are a bargain. A 14​-mile taxi ride takes 16 minutes and costs ​$11.20. You want t
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Carrie planted 48 tulips in 12 minutes . How many did she plant per minute
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What are the values of x and y?
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3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
nirvana33 [79]

Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.99, so z = 1.28

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

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3 years ago
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