Answer:
The answer is "
".
Step-by-step explanation:
please find the complete question in the attached file.

![=\frac{1}{10} (\frac{x^3}{3})^{5}_{-5}\\\\=\frac{1}{30}[5^3+5^3]\\\\=\frac{2}{30}(125)\\\\=\frac{1}{15} \times 125\\\\=\frac{25}{3}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B10%7D%20%28%5Cfrac%7Bx%5E3%7D%7B3%7D%29%5E%7B5%7D_%7B-5%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B30%7D%5B5%5E3%2B5%5E3%5D%5C%5C%5C%5C%3D%5Cfrac%7B2%7D%7B30%7D%28125%29%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B15%7D%20%5Ctimes%20125%5C%5C%5C%5C%3D%5Cfrac%7B25%7D%7B3%7D)
Answer:
AB ≈ 15.7 cm, BC ≈ 18.7 cm
Step-by-step explanation:
(1)
Using the Cosine rule in Δ ABD
AB² = 12.4² + 16.5² - (2 × 12.4 × 16.5 × cos64° )
= 153.76 + 272.25 - (409.2 cos64° )
= 426.01 - 179.38
= 246.63 ( take the square root of both sides )
AB =
≈ 15.7 cm ( to 1 dec. place )
(2)
Calculate ∠ BCD in Δ BCD
∠ BCD = 180° - (53 + 95)° ← angle sum in triangle
∠ BCD = 180° - 148° = 32°
Using the Sine rule in Δ BCD
=
=
( cross- multiply )
BC × sin32° = 12.4 × sin53° ( divide both sides by sin32° )
BC =
≈ 18.7 cm ( to 1 dec. place )
Answer:
BC= 23.0km (nearest tenth)
Step-by-step explanation:
Please see the attached picture for full solution.
Answer:
(2, 8) and (3, 11) --- > For example
Step-by-step explanation:
Plug in any number for x
I will use 2.
So if the equation is y = 3x + 2, then the new equation will be ...
y = 3(2) + 2
y = 6 + 2
y = 8 ----> One coordinate can be (2, 8)
Another number you could use is 3.
y = 3(3) + 2
y = 9 + 2
y = 11 ----> Another coordinate may be (3, 11)
The Answer should be 7.5
If you would like me to elaborate, let me know