All you do is find the are which would be a=l×w or a=28×15 or 420 or to the nearest 10th would be also 420
Answer:
∠1 + ∠2 + ∠3 = 180°
Step-by-step explanation:
Given : AB II XC
To Show : ∠1 + ∠2 + ∠3 = 180°
Proof: Here, given that AB is parallel to the line XC
⇒ ∠4 = ∠2 (Pair of Alternate angles as AB II XC) ......... (1)
and ∠5 = ∠3 (Pair of Alternate angles as AB II XC) ........... (2)
Now, ∠1 + ∠4 + ∠5 = 180° ( Straight Angle)
But, from above (1) and (2)
∠1 + ∠2 + ∠3 = 180° ( as ∠4 = ∠2, ∠5 = ∠3)
Hence, ∠1 + ∠2 + ∠3 = 180°
Hence Proved.
for
f(x)= 4x + 3
f(0) would be
f(0)= 4*0 + 3, or just 3
x is just set to 0 and everything it multiplies with vanishes
if x < 0 the result is smaller then 3
if x > 0 the result is bigger than 3
You seemed to have asked this multiple times. I have answered one of yours. Its D.
Answer:
<h3>option :c is correct..ok</h3>
