1)volume of the pipeline
The pipeline is a cylinder, therefore;
Volume (cylinder)=πr²h
r=radius
h=height of the cylinder
diameter=6 in*(1 ft / 12 in)=0.5 ft
raius=diameter / 2=0.5 ft / 2=0.25 ft.
height=5280 ft
Volume (pipeline)=π(0.25 ft)²(5280 ft)=330π ft³≈1036.73 ft³.
2) we calculate the number of barrel
1 mile of oil in this pipeline is 330π ft³ of oil.
1 barrel of crude------------------5.61 ft³
x----------------------------------330π ft³
x=(1 barrel*330π ft³) / 5.61 ft³=184.8 barrels
3) we calculate the price.
1 barrel---------------$100
184.8 barrels---------- x
x=(184.8 barrels * $100) / 1 barrel=$18,480
Solution: ≈$18,480
Answer: 3.16
The first point, T = (x1,y1), and the second point, U = (x2,y2). Can be approximated as 3.16,so the distance between the two points is 3.16 units.
A) 2x-7=13
2x=20
x=10
B) 3x+4=25
3x=21
x=7
Answer:
Step-by-step explanation:
3+√5 is a root.
so 3-√5 is also a root
or (x-(3-√5)) is also a factor of f(x)
Answer:
12
Step-by-step explanation:
a=bh x 1/2
If you plug in 3=b and 8=h it is now
a= 3 x 8 x 1/2
3x8 is 24 times 1/2 is 12
Hope this helps :)
