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LenKa [72]
2 years ago
12

2 4/5 divided by (6 divided by 2 1/2)

Mathematics
1 answer:
netineya [11]2 years ago
6 0

2 4/5÷(6÷2 1/2)

2 4/5÷2 2/5

1 1/12

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3 years ago
at which values of x does the graph of f(x)=x^2-x-2/(x^2-1)(x^2-16) have a vertical asymptope? check all that apply
katen-ka-za [31]

Answer:

x = -4, 1, 4

Step-by-step explanation:

The function is given as:

f(x) = (x² - x -2)/[(x² - 1)(x² -16)]

We want to find the values of x where the graph will have vertical assymptote.

Vertical asymptotes are defined as vertical lines which correspond to the values of x that will make the denominator of a rational function to be zero.

Thus, to get the values of x that we will have vertical assymptotes, we have to equate the denominator to zero.

We have;

[(x² - 1)(x² -16)] = 0

Thus,

x² - 1 = 0

Or

x² - 16 = 0

So;

x² = 1

x = √1

x = 1

Or

x² = 16

x = ±√16

x = ±4

Values of x that give vertical assymptote are;

x = -4, 1, 4

3 0
3 years ago
A rectangle has a height of 4 and a width of 2x2 – 2.
svetlana [45]

Answer:

area of a rectangle =WxH

given

H=4

W=2x2-2

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therefore

A=4x2

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5 0
3 years ago
A new hard drive costs $225, plus $40 per hour for
allsm [11]

Answer:

4 hours

Step-by-step explanation:

y= 40x +225

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40* x can be maximum 160  so x= 160 /40= 4

5 0
3 years ago
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