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tester [92]
2 years ago
15

What is B^2 ? Square root of B^2 is ?

Mathematics
1 answer:
Andrews [41]2 years ago
3 0

Answer:

<em><u>w</u></em><em><u>h</u></em><em><u>a</u></em><em><u>t</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>B</u></em><em><u>^</u></em><em><u>2</u></em><em><u> </u></em><em><u>?</u></em>

ans - 1 byte2

<em><u>Square</u></em><em><u> </u></em><em><u>root</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>B</u></em><em><u>^</u></em><em><u>2is</u></em><em><u> </u></em><em><u>?</u></em>

ans - Square root(byte^2) =

1 byte

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The difference of a number s and 6
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Answer:

idk

Step-by-step explanation:

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What is the nth term of the sequence? 4, 2, 0, –2, ..
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' n '    the 'n'th term

1               4
2               2 
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3 years ago
The derivative of y with respect to x, when y = 3e^5x - 2 is:
Ede4ka [16]
Answer: 15e^5x

Step - by - step

y=3e^5x - 2

By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].

d/dx [ 3e^5x ] + d/dx [ -2 ]

Evalute d/dx [ 3e^5x ]

Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].

3 d/dx [ e^5x ] + d/dx [ -2 ]

Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.

To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]

Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.

3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]

Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]

Multiply 5 by 3
15e^5x + d/dx [-2]

Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x
5 0
10 months ago
How to construct a triangle with side lengths 10 cm and 14 cm and an angle between them of 60 degrees.
Yuliya22 [10]

Answer:

We draw line AB which is perpendicular to the 14 cm side

Since Angle C is 60 degrees that makes angle CAB = 30 degrees

Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm

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Line AB^2 = 10^2 - 5^2 = 75

Line AD^2 = AB^2 + BD^2

Line AD^2 = 75 + 81

Line AD^2 = 156

Line AD = 12.4899959968

Line AB = Sqr root (75) = 8.6602540378

Angle D = arc sine  (8.6602540378 / 12.4899959968)

Angle D = 43.898 degrees

Angle A = 180 - 60 - 43.898 = 76.102 degrees

*****************************************************************

Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.

Step-by-step explanation:

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Vikentia [17]
Don't look at this comment.. I messed up the first time so, yeah.
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