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3 years ago

15

What is B^2 ? Square root of B^2 is ?

1 answer:

Andrews [41]3 years ago

3 0

Answer:

<em><u>w</u></em><em><u>h</u></em><em><u>a</u></em><em><u>t</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>B</u></em><em><u>^</u></em><em><u>2</u></em><em><u> </u></em><em><u>?</u></em>

ans - 1 byte2

<em><u>Square</u></em><em><u> </u></em><em><u>root</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>B</u></em><em><u>^</u></em><em><u>2is</u></em><em><u> </u></em><em><u>?</u></em>

ans - Square root(byte^2) =

1 byte

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To find the value of y from a given value of x, find the position of x on the x-axis, then trace vertically until you meet the line. Once you meet the line, trace horizontally to the y-axis to find the corresponding value of y.

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From inspection of the graph,

when x = 1, y = -1

when x = 0, y = 2

when x = 2, y = -4

Therefore,

$\begin{array}{| c | c |}\cline{1-2} x & y\\\cline{1-2} 1 & -1 \\\cline{1-2} 0 & 2 \\\cline{1-2} 2 & -4 \\\cline{1-2}\end{array}$

To find the equation of the line, find the slope:

$\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{2-(-1)}{0-1}=-3$

Then use one of the points and the found slope with the point-slope form of a linear equation: $y-y_1=m(x-x_1)$

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