Question

Sameeha is taking an antibiotic prescription. Sameeha takes 50mg on the first day, and then 50mg each day for the next 6 days. The iteration that describes the amount of the medication in Sameeha's system at time t is f(t)= 0.40t +50 where t0=50 . How much medication is in Sameeha's system after she takes her last dose of the medication? Round to the nearest tenth, if needed.
82.9 mg
78 mg
50 mg
83.2 mg

Answer 1

The amount of medication in Sameeha's system after she takes her last dose of the medication is (d) 83.20

How to determine the amount of medication

The function is given as:

f(t) = 0.40t + 50

Where

t0 = 50

This means that:

On day 1, we have:

$f(50) = 0.40 * 50 + 50$

$f(50) = 70$

On day 2, we have:

$f(70) = 0.40 * 70 + 50$

$f(70) = 78$

On day 3, we have:

$f(78) =0.40 * 78 + 50$

$f(78) =81.2$

On day 4, we have:

$f(81.2) = 0.40 * 81.2 +50$

$f(81.2) = 82.48$

On day 5, we have:

$f(82.48) = 0.40 * 82.48 + 50$

$f(82.48) = 82.99$

On day 6, we have:

$f(82.99) = 0.40 * 82.99 + 50$

$f(82.99) = 83.20$

Hence, the amount of medication in Sameeha's system after she takes her last dose of the medication is (d) 83.20

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