Answer:
the correct answer would be 13.75
Answer: z=1/2 or 0.5
Step-by-step explanation: 1. Subtract 19/2 to both sides. 13-19/2 is equal to 7/2 or 3.5." So then you're left with 7z=3.5
2. Divide by 7 to both sides. 3.5/7= 0.5.
3. z=0.5
Write the decimal number as a fraction (over 1)
23.8 = 23.8 / 1
Multiplying by 1 to eliminate 1 decimal places
we multiply top and bottom by 1 10's
Numerator (N)
N = 23.8 × 10 = 238
Denominator (D)
D = 1 × 10 = 10
N / D = 238 / 10
Simplifying the fraction
238/10 = 119/5= 23 4/5
FINAL ANSWER: 23 4/5
Answer:
12-7/5-3=5/2
Step-by-step explanation:
We have the equations:
<span>C(n,k) / C(n,k+1) = 1/2
</span>C(n,k+1) / C(n, k+2) = 2/3<span>
</span>[n! / (n-k)!k! ]/[ <span>n! / (n- (k+1))! (k+1)! ]= 1/2
You can cancel out similar terms. The definition of factorials is this
n! = n(n -1)(n -2)(n -3)...1
So,
</span> (n- (k+1))! (k+1)! / (n-k)!k! = 1/2
(n- k - 1)(n - k - 1 -1)! (k+1)(k + 1 - 1)! / (n-k)!k! = 1/2
(n- k - 1)(n - k - 2)! (k+1)(k)! / (n-k)!k! = 1/2
Cancel out terms.
(n- k - 1)(n - k - 2)! (k+1)/ (n-k)!= 1/2 [eqn 1]
[n! / (n-k+1)!(k+1)! ]/[ n! / (n- (k+2))! (k+2)! ]= 2/3
(n- (k+2))! (k+2)! / (n-(k+1))!(k+1)! = 2/3
(n- k-2)! (k+2)! / (n-k-1)!(k+1)! = 2/3
(n- k-2)(n - k -3)! (k+2)( k+1)k! / (n-k-1)(n-k-2)(n-k-3)!(k+1)k! = 2/3
Cancel out terms
(k+2)/ (n-k-1) = 2/3
You can solve for n in terms of k and substitute this to the fist equation which will allow you to solve for k.