Answer: you would do lxw and W=5 and L=2 so what u would do it 5x2=10 so your answer is 10
Answer:
Step-by-step explanation:
x![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx)
XE[_4.2,2.2]
Answer:
Step-by-step explanation:
We will be using 2 properties of radicals in this simplification (outlined below).
<em>Let's simplify this:</em>
First answer choice is right.
Answer:
10.3
Step-by-step explanation:
Let the given points be the endpoints of a right triangle. The horizontal change in x is from 4 to -5 and is negative 9; the vertical change in y is from -2 to+ 3 and is +5.
The desired distance is found using the Pythagorean theorem:
d = √(9² + 5²) = √106, or 10.3 (to the nearest tength)
Y=25 because 19-2+8 equals 25 so y = 25
