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Allushta [10]
2 years ago
11

Each student will need 5 rubber bands. There are 8 students. Rubber bands come in bags of 9. How many bags will be needed. How m

any rubber bands will be left over
Mathematics
1 answer:
kumpel [21]2 years ago
3 0
You will need to buy 5 bags, which would be 45 rubber bands. 8x5 is 40 so you will have 5 rubber bands left.
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Ethan pays 52.80 for some more f the boxes work out the number of boxes he buys 1 box 2.40 2 4.80 and 5 12 10 24
Slav-nsk [51]
The pricing of the boxes seems to be consistently 2.40 per box. Ethan's cost is
.. 52.80 = 2.40 * (# of boxes)
.. 52.80/2.40 = (# of boxes)
.. 22 = # of boxes

Ethan has bought 22 boxes for 52.80.
5 0
3 years ago
PLS help I will give brainliest to the one who will answer me first.<br><br>pic is not blurry
marissa [1.9K]

Answer:

Sample answer: The median of the means for Grade 8 is greater than for Grade 12. However, there is less variation in the data for Grade 12 since the length of the box for Grade 12 is shorter than the one for Grade 8.

5 0
2 years ago
Add and simplify: 9/16 + 1/2=?<br> 5/8<br> 7/16<br> 1 1/16<br> 1 5/9
Rina8888 [55]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
The area of a square for on a scale drawing of 100 square centimeters and the scale drawing to 1 cm: 2 feet what is the area of
lilavasa [31]

Answer:

1.\boxed{\text{400 ft}^{2}}; 2. \boxed{\frac{1}{3716}}

Step-by-step explanation:

Step 1. Calculate the area of the floor

If the area A₁ of a square floor on the scale drawing is 100 cm², the length of a side is 10 cm.

The side length l of the actual floor is  

l = 10 cm × (2 ft/1 cm) = 20 ft

The area A₂ of the floor is  

A = l² = (20 ft)² = \boxed{\text{400 ft}^{2}}\\

Step 2. Calculate the area ratios

We must express both areas in the same units.  

Let's express the area of the room in square centimetres.

l = 20 ft ×  (12 in/1 ft) = 240 in

l = 240 in × (2.54 cm/1 in) = 609.6 cm

A₂ = l² = (609.6 cm)² = 371 612 cm²

The area A₁ on the scale drawing is 100 cm².

The ratio of the areas is

\frac{A_{1}}{ A_{2}} = \frac{100}{371612} = \frac{1 }{3716}\\

The ratio of the area in the drawing to the actual area is \boxed{\frac{1}{3716}}

8 0
3 years ago
A 40 N force is applied to an object with a mass of 0.1 kg on a frictionless surface. What is the acceleration of the object?
tino4ka555 [31]

Answer:

400

Step-by-step explanation:

40 divided by .1

4 0
3 years ago
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