What is it? The question?
(16/18)
(24/27)
You just times 8 and 9 by the same number, like:
(8•2/9•2)=(16/18)
(8•3/9•3)=(24/27)
You could do any number:
(8•100/9•100)=(800/900)
I think it’s d the readers choice of word when responding to a text .
First write the equation
3/n = 5
Multiply both sides by n
3/n * n = 5 * n
Simplify
3 = 5 * n
Divide both sides by 5
3/5 = 5 * n/5
Simplify
3/5 = n
Divide
0.6 = n
So 3/0.6 = 5
Answer:
➩ 
Step-by-step explanation:

➨ We can also solve by completing both squares, however. Since we can pull out the square root.
➩ Define of Absolute Value/Square Root
➩ 
Thus, our new equation is ➩ 
To solve an absolute-value equation, let there be two conditions.
➨ Where x ≥ 0

Move x to another side

➨ Where x < 0
