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2 years ago

PLS HELP. Find the value of a, AB, BC, CD, AD in the parallelogram. Pls show work.

Mathematics

1 answer:

BaLLatris [955]2 years ago

6 0

Answer:

A= 21

Step-by-step explanation:

a=19.5+1.5=21

21+2.9=23.9

2(21)-18.1

Lines AB and CD are congruent.

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What is the answe ?????

vladimir1956 [14]

Hello there!

The right prime factorization is

2*2*2*3*11 because 2 and 3 and 11 are prime.

Take a look at the words "prime" and "factorization"

Can you see something that looks like "prime factors?" Exactly!

2 is prime. 3 is prime. 11 is also prime.

A prime number is only divisible by 1 and itself.

What is the value of 5+2*15+(12*4)?

If you remember "Please Excuse My Dear Aunt Sally" that's great as long as you know what that means.

P = Parentheses

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5+2*15+(12*4)=5+2*15+(48)=5+30+48=83

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2 years ago

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Ilia_Sergeevich [38]

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3 0

1 year ago

Read 2 more answers

Which ordered pair is a solution of 6x+3y=15

victus00 [196]

6•2+3•1=15 is the answer

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2 years ago

Drag the tiles to the correct boxes to complete the pairs.

Len [333]

Answer:

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4} \implies 2^{-32}$

2. $2^4 . (2^2)^{-2} \implies 1$

3. $(-2^{-4}).(2^2)^0 \implies -2^8$

4. $(2^2).(2^3)^{-3} \implies 2^{-5}$

Step-by-step explanation:

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4}$ :

$= \frac{ ( - 2 ^ 2 ) ^ { - 6 } } { ( 2 ^ { - 5 } ) ^ { - 4 } } = \frac{2^{-12}}{2^{20}} = 2^{-12-20}=2^{-32}$

2. $2 ^ 4 . ( 2 ^ 2 ) ^ { - 2 }$ :

$= 2^4 \times \frac{1}{2^4} = 1$

3. $(-2^{-4}).(2^2)^0$ :

$= (-2^4)^2 \times 1 = -2^8$

4. $(2^2).(2^3)^{-3}$ :

$= 2^4 \times \frac{1}{2^9} =\frac{1}{2^5} =2^{-5}$

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2 years ago

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Which decimal number is equivalent to 1/10 ? A.1 B.0.1 C.0.01 D.0.001

elena-14-01-66 [18.8K]

If you would like to find the decimal number which is equivalent to 1/10, you can do this using the following step:

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2 years ago