How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?
sveta [45]
There are 6 digits. Each digit can take ten different numbers except for the first digit since it cannot be zero.
So:
9 x 10 x 10 x 10 x 10 x 10
900000 numbers.
Another way of thinking about this is to just count up to 999,999. Obviously there are 999,999 different numbers here. But since our number has to have 6 digits in them, we have to delete 99,999 numbers. Thus there are 900,000 different numbers.
Answer: 60
Step-by-step explanation: multiply four by 15 in this case take four 15's and add them all up
Answer:
Remember the key word”factor” which means to multiply. Multiple all those numbers by 3!
Step-by-step explanation:I’m going to do 2 of them and you can do the last one (2,1)x3= the dilation (6,3). (3,0)x 3 gives the dilation (9,0). (1,-2)x3 gives the dilation of (3,-6). See it’s very easy.
Answer: I think #2 is either A or C
Step-by-step explanation: Hope it helped! :)