Let Bea = x
Therefore Andrew = x + 2
Chris = x - 3
Andrew * Chris = 66
(x + 2)(x - 3) = 66 Remove the brackets.
x^2 + 2x - 3x - 6 = 66
x^2 - x - 6 = 66 Subtract 66 from both sides.
x^2 - x - 72 = 0
(x - 9)(x + 8) = 0
Find the possible values of Bea's age
x - 9 = 0
x = 9 That value works. She can be plus 9 years old.
x + 8 = 0
x = - 8. There's no way she can be - 8 years old
So Bea is 9.
9 <<<<<< Answer
Answer:
Option 3) -6,-5/2
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
Answer:
the figures are congruent because they have 3 congruent sides and three congruent angles
Answer:
x = 5
Step-by-step explanation:
0.8x - 0.3 - 0.7x = 0.2
0.8x - 0.7x = 0.2 + 0.3
0.1x = 0.2 + 0.3
0.1x = 0.5
Answer:
I believe that B is the correct answer!
Step-by-step explanation:
The (x+5) can cancel
Then in the numerator (x^2-25) can be factored into (x-5)(x+5) through difference of squares.
Then in the denominator the (x-5)^2 can be stretched out to (x-5)(x-5)
Lastly the (x-5) on the top and bottom will cancel resulting in result B
I hope this helped!