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BartSMP [9]
2 years ago
7

Complete the table below. X Y=3x^2 Y=3x 0 0 1 1 2

Mathematics
1 answer:
wlad13 [49]2 years ago
5 0

Answer:

y= 3x^2 y= 3^x

1. 3. 3

2. 12. 9

Step-by-step explanation:

3(1)^1

3

3^1

3

3(2)^2

3(4)

12

3^2

9

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If the suspect is found guilty, then he will go to prison.
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Answer:

If the suspect goes to prison, then he was found guilty.

Step-by-step explanation:

Means the same thing. If you guilty, you get the jail time. Same thing as before. The only other one it could be is the first one. But you could argue that one.

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Convert. If necessary, round to the nearest tenth.<br> 1.5 oz ≈ ___g
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42.52 g

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4 0
3 years ago
Solve the system by substitution.<br> y = -3x +4<br> y = 2
erma4kov [3.2K]

Answer:

(2/3,2)

Step-by-step explanation:

3*2/3+4

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5 0
2 years ago
Write the following statement as a conditional statement. A kite is a figure with four sides. If a figure has four sides, then i
aleksandr82 [10.1K]
The statement that should be rewritten as conditional statement is:
<span>A kite is a figure with four sides.
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If a figure has four sides, then it is a kites</span>
7 0
3 years ago
Read 2 more answers
The equation a<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class=
andrezito [222]

Answer:

\displaystyle \left(\alpha+1\right)\left(\beta + 1\right)  = \frac{a+c-b}{a}\:\: \left(\text{ or } 1+\frac{c-b}{a}\right)

Step-by-step explanation:

We are given the equation:

ax^2+bx+c=0

Which has roots α and β.

And we want to express (α + 1)(β + 1) in terms of <em>a</em>, <em>b</em>, and <em>c</em>.

From the quadratic formula, we know that the two solutions to our equation are:

\displaystyle x_1 = \frac{-b+\sqrt{b^2-4ac}}{2a}\text{ and } x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}

Let <em>x</em>₁ = α and <em>x₂ </em>= β. Substitute:

\displaystyle \left(\frac{-b+\sqrt{b^2-4ac}}{2a} + 1\right) \left(\frac{-b-\sqrt{b^2-4ac}}{2a}+1\right)

Combine fractions:

\displaystyle =\left(\frac{-b+2a+\sqrt{b^2-4ac}}{2a} \right) \left(\frac{-b+2a-\sqrt{b^2-4ac}}{2a}\right)

Rewrite:

\displaystyle = \frac{\left(-b+2a+\sqrt{b^2-4ac}\right)\left(-b+2a-\sqrt{b^2-4ac}\right)}{(2a)(2a)}

Multiply and group:

\displaystyle = \frac{((-b+2a)+\sqrt{b^2-4ac})((-b+2a)-\sqrt{b^2-4ac})}{4a^2}

Difference of two squares:

\displaystyle = \frac{\overbrace{(-b+2a)^2 - (\sqrt{b^2-4ac})^2}^{(x+y)(x-y)=x^2-y^2}}{4a^2}

Expand and simplify:

\displaystyle = \frac{(b^2-4ab+4a^2)-(b^2-4ac)}{4a^2}

Distribute:

\displaystyle = \frac{(b^2-4ab+4a^2)+(-b^2+4ac)}{4a^2}

Cancel like terms:

\displaystyle = \frac{4a^2+4ac-4ab}{4a^2}

Factor:

\displaystyle =\frac{4a(a+c-b)}{4a(a)}

Cancel. Hence:

\displaystyle = \frac{a+c-b}{a}\:\: \left(\text{ or } 1+\frac{c-b}{a}\right)

Therefore:

\displaystyle \left(\alpha+1\right)\left(\beta + 1\right) = \frac{a+c-b}{a}

4 0
3 years ago
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