Answer:
2
Step-by-step explanation:
2/2+1
2
Answer:
Step-by-step explanation:
2 = ⅔[6] + b
4
If you want it in <em>Standard Form</em>:
y = ⅔x - 2
- ⅔x - ⅔x
_________
−⅔x + y = −2 [We do not want fractions in our standard equation, so multiply by the denominator to get rid it.]
−3[−⅔x + y = −2]
_______________________________________________
−5 = 3⁄2[10] + b
15
If you want it in <em>Standard</em><em> </em><em>Form</em>:
y = 3⁄2x - 20
- 3⁄2x - 3⁄2x
__________
−3⁄2x + y = −20 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]
−2[−3⁄2x + y = −20]
* Parallel Lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>], so ⅔ and 3⁄2 remain the way they are.
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Answer:
Step-by-step explanation:
Mass (m kg) frequency mass (m kg) c.f.
0 < m ≤ 0.1 4 m ≤ 0.1 4
0.1 < m ≤ 0.2 6 m ≤ 0.2 10
0.2 < m ≤ 0.5 58 m ≤ 0.5 68
0.5 < m ≤ 0.8 28 m ≤ 0.8 96
0.8 < m ≤ 1.0 4 m ≤ 1.0 100
Total number of parcels surveyed = cumulative frequency = 100
Answer:
x > ten sevenths
Step-by-step explanation:
We want to solve for x in the inequality:
We multiply through by 4 to clear the fraction.
Group similar terms to get:
The first choice is correct
Answer:
Step-by-step explanation:
given that the following data represent the discrete probability distribution for the number of stars that reviewers have a first edition statistics reference book.
Stars 5 4 3 2 1
Probability 25% 35% 20% 10% 10%
H0: Second edition is as per the above probabilities
Ha: atleast one is different from the above probability
(two tailed chi square test)
Alpha = 0.025
Assuming H0 to be true we calculate expected frequencies for total 80
chi square calculatons are shown below
df = 4
5 4 3 2 1 Total
Observed 28 28 13 6 5 80
Expected 20 28 16 8 8 80
chi square
(O_E)^2/E 3.2 0 0.5625 0.5 1.125 5.3875
p value =0.1455
Since p value >0.025, we accept H0
The expected requency of three-star reviews is ________.16