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3 years ago

How do you graph 34,-8?

Mathematics

1 answer:

miss Akunina [59]3 years ago

3 0

Answer:

on the x axis you find 34 and go to the y axis and find -8 and then draw your finger until they meet. Wherever they meet is your point.

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Sean recorded everyone's number cube rolls during the game

ivann1987 [24]

Answer:

His assumption is based upon his belief that the average is fixed and not just random; the number each person gets is random, and with none more likely than another.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If u(x) = x^5 - x^4 + x^2 and v (x) = -x^2 which expression is equivalent to ( u/ v) (x)

yawa3891 [41]

Answer:

$(u/v)(x)=-x^{3}+x^{2}-1$

Step-by-step explanation:

You have the following functions:

$u(x)=x^{5}-x^{4}+x^{2}\\v(x)=-x^{2}$

Therefore $(u/v)(x)$ indicates that you must divide both functions, as you can see below:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}$

Simplify it. Therefore, you obtain:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}\\\\(u/v)(x)=-x^{3}+x^{2}-1$

3 0

4 years ago

Read 2 more answers

V square+6v-59=0<br> answer in one equation

Tema [17]

X= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
a=1
b=6
c=-59
x= $\frac{-6+/- \sqrt{(6)-4(1)(-59)} }{2(1)}$
x= $-3+ 2\sqrt{17}$ and $-3- 2\sqrt{17}$

8 0

3 years ago

3) At a school several teachers were holding a contest to see which class could earn the most trivia points. Mrs. Clawson's clas

Snezhnost [94]

Answer:

Mean: 89

Median: 90

Mode: 94

Range: 12

5 0

3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

3 years ago