I’m sorry I can’t help but pray
Answer: the graph farthest to the right is almost correct. If you substitute values for x in the function f(x)= -3√x , the output does not match the curve on the graphs shown.
If you have a choice that includes only a curve to the right of the y- axis, that would be better.
Step-by-step explanation: Square roots of Negative x-values will result in imaginary numbers. Otherwise the graph with the curve passing through coordinates (1,-3) (4,-6) and (9,-9) is a good choice.
(And ask your teacher about the square root of negative numbers on this graph.)
A negative slope means the line would be going downward, so you would go down first (instead of up as with a positive slope), then over right.
Therefore, you would go down 4 (or negative 4 considering you are going down) and right 1.
Rise over run still applies here. Rise over run is a fancy way of saying to put the number (or slope) in fraction form.
-4 as a fraction would be -4/1.
So start at (5,3), go down 4 and over 1, repeatedly and you got it.
**Just remember the rise over run can be confusing with negative slopes.**
<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>
