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2 years ago

Helppppp plsssssss- :

Mathematics

2 answers:

Luba_88 [7]2 years ago

5 0

Answer:

4: 4

5: $6\frac{2}{3}$

6: 14

7: 10

8: 3 1/5

9: 4 1/2

Step-by-step explanation:

3/(3/4)=

3*(4/3) =

5/(3/4)=

5*(4/3)=

6 2/3

8/(4/7) =

8*(7/4) =

8*1.75 =

6/(3/5) =

6*(5/3) =

(6*1)+(6*(2/3))=

6+4=

2/(5/8) =

2*(8/5) =

2*1.6 =

3.2 =

3 1/5

4/(8/9)=

4*(9/8)=

4.5 =

4 1/2

rewona [7]2 years ago

4 0

Answer:

Q4 = 4 || Q5 = 6 2/3 || Q6 = 4 4/7 || Q7 = 10 || Q8 = 3 1/3 || Q9 = 4 1/2

Step-by-step explanation:

In order to divide fractions, you just have to turn it into multiplying!
Flip the second fraction in the number sentence and then multiply!

Example: 5 divided by 6/7

Keep 5 as it is. Flip 6/7 to 7/6. 5 x 7/6 = 35/6

Now, simplify it! Simplifying is very simple. You just have to divide until they can't be divided anymore.

35/6 simplified = 5 5/6.

Reason:

How many 6's are in 35? 5 R: 5

So, then it would be 5 5/6.

Hope this helped and this was correct! If you have any more questions, I'll be here to answer them!

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Please help!!! will give brainliest

mina [271]

Answer:

The answer is B

Step-by-step explanation:

3 to the forth power = 81

3 to the second power = 9

81/9 = 9

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3 years ago

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Classify the expression, name the operation(s) and identify any variables. 3s – 5

Elodia [21]

Numerical, subtraction, s

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2 years ago

hey thereee! please help me with this, or tell me what topic this is under because I haven't learn this but i would like to try

Jlenok [28]

Answer:

B.)70

Step-by-step explanation:

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3 years ago

Will give brainliest!

Gala2k [10]

Check the picture below, it hits the ground when y = 0.

$\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o \\\\
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{0}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{162}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}
\\\\\\
h(t)=-16t^2+0t+162\implies 0=-16t^2+162\implies 16t^2=162
\\\\\\
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6 0

3 years ago

Determine whether the relation R on the set of all Web pages is reflexive, symmetric, antisymmetric, and/or transitive, where (a

xxMikexx [17]

Answer:

a) R is reflexive, R is not symmetric, R is not anti-symmetric, R is transitive.

b) R is reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

c) R is not reflexive, R is symmetric, R is not anti-symmetric, R is not transitive.

Step-by-step explanation:

(a, b) ∈ R if and only if everyone who has visited Web page a has also visited Web page b.

Obviously R is reflexive (aRa)

Everyone who has visited Web page a has also visited Web page a

R is not symmetric (aRb does not imply bRa)

If everyone who has visited Web page a has also visited Web page b does not mean that everyone who has visited Web page b has also visited Web page a

R is not anti-symmetric (aRb and bRa does not imply a=b)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page a does not mean the web pages are the same.

R is transitive (aRb and bRc implies aRc)

If everyone who has visited Web page a has also visited Web page b and everyone who has visited Web page b has also visited Web page c implies that everyone who has visited Web page a has also visited Web page c.

(a, b) ∈ R if and only if there are no common links found on both Web page a and Web page b.

R is obviously reflexive (aRa)

R is symmetric (aRb implies bRa)

if there are no common links found on both Web page a and Web page b, then there are no common links found on both Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there are no common links found on both Web page a and Web page b and there are no common links found on both Web page b and Web page a does not mean a and b are the same web page.

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a and c have a common link and b has no external links at all.

Then obviously (a,b)∈R and (b,c)∈R since b has no links, but (a,c)∉R because they have a common link.

(a, b) ∈ R if and only if there is at least one common link on Web page a and Web page b

R is not reflexive

If the web page a does not have any link at all, then a is not related to a.

R is symmetric (aRb implies bRa)

if there is at least one common link found on Web page a and Web page b, then there is at least one common link found on Web page b and Web page a.

R is not anti-symmetric (aRb and bRa does not imply a=b)

if there is at least one common link found on Web page a and Web page b and there is at least one common link found on Web page b and Web page a does not mean the web pages are the same

R is not transitive (aRb and bRc does not imply aRc)

Consider for example three web pages a, b and c such that a has only two links L1 and L2, b has only two links L2 and L3 c has only two links L3 and L4.

Then (a, b) ∈ R since a and b have the common link L2, (b, c) ∈ R for b and c have the common link L3, but a and c have no common links, therefore (a,c)∉R

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3 years ago