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2 years ago

Teachers who take a code-emphasis approach to instruction generally do not discuss the meanings of words being taught.

1 answer:

5 0

Code-emphasis method could be used in a middle class area school because it produces better result than a meaning-emphasis method.

<h3>Code emphasis</h3>

Code emphasis is the teaching of reading through the use of an alphabetic code which are arranged in specific categories or combinations. The emphasis on letters and letter combinations is used.

Code-emphasis method could be used in a middle class area school because it produces better result than a meaning-emphasis method.

Find out more on code emphasis at: brainly.com/question/26135905

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A projectile is projected from the origin with a velocity of 30

Sliva [168]

For this we will use kinematic equations.

We need the time of flight to compute the range.

With the given information, the most useful formula is:

Δy=v0yt−g2t2

Because our equation is taking only vertical motion into account,

v0y=30sin(45)

Because we are looking for the range of the object,

Δy=0

This leaves us with only one unknown: t

0=30sin(45)t−g2t2

g2t2=30sin(45)t

g2t=30sin(45)

t=60gsin(45)

For horizontal distance, the formula we need is:

Δx=v0xt

Because we are taking into account the horizontal range,

v0x=30cos(45)

In substituting our derived values into the equation we can see that:

Δx=30cos(45)∗60gsin(45)

Range=30cos(45)∗60gsin(45)

6 0

2 years ago

(I WILL GIVE THE CORRECT PERSON BRAINIEST )

astra-53 [7]

C pizz sales are affected by popular diets

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3 years ago

Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o

Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

Carbon (C): 47.37 grams
Hydrogen (H): 10.59 grams
Oxygen (O): 42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

Carbon (C): $\frac{47.37 grams}{12 \frac{g}{mole} }$ = 3.95 moles
Hydrogen (H): $\frac{10.59 grams}{1 \frac{g}{mole} }$ = 10.59 moles
Oxygen (O): $\frac{42.04 grams}{16 \frac{g}{mole} }$ = 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Carbon (C): $\frac{3.95 moles}{2.63 moles }$ = 1.5
Hydrogen (H): $\frac{10.59 moles}{2.63 moles }$ = 4
Oxygen (O): $\frac{2.63 moles}{2.63 moles }$ = 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

Carbon (C): 1.5× 2= 3
Hydrogen (H): 4× 2= 8
Oxygen (O): 1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

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2 years ago

1. Kepler's three laws resulted from his careful analysis of ____ data, and were not derived from a mathematical model.

Sav [38]

<h2>1. Right answer: Observational </h2>

Kepler formulated the three laws of planetary motion <u>from observations made by</u> the Danish astronomer <u>Tycho Brahe of the orbit of Mars. </u>

These laws were enunciated to mathematically describe the movement of the planets in their orbits around the Sun. However, the scientific resources existing in his time did not allow him to prove these laws. It was Newton who did it after having developed the Differential and Integral Calculus and formulating the Laws of Universal Gravitation.

<h2>2. Right answer: Aristotelian </h2>

Aristotle mistakenly thought that the Earth was the center of the universe, thus establishing a <u>geocentric cosmological model. </u>

According to this model, Aristotle proposed that the universe (the cosmos) was spherical and finite, with the Earth immobile at its center, composed of the four fundamental elements (made up of spherical layers): ground, water, air and fire; and the Sun along with the fixed planets in their respective concentric spheres revolving around the Earth. The outermost sphere being that of the stars and all these external elements being made of a fifth element which he called ether.

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3 years ago

The ACT English test consists of _____ questions.

yulyashka [42]

There are 75 questions + 1 essay on the English ACT

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3 years ago

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