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2 years ago

45 POINTS!! Please help me solve this Table I’m having a hard time this is my last chance to pass!

Mathematics

1 answer:

Anettt [7]2 years ago

8 0

Solution:

Given function:

f(x) = x - 1

Solution (x = -2):

f(x) = x - 1
=> -2 - 1
=> -3

Solution (x = 0):

f(x) = x - 1
=> 0 - 1
=> -1

Solution (x = 2):

f(x) = x - 1
=> 2 - 1
=> 1

Solution (x = 3):

f(x) = x - 1
=> f(x) = 3 - 1
=> 2

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Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un

Snowcat [4.5K]

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

the velocity of first car,

$v_1\ =\ 20i\ +\ 25j$

and the velocity of second car

$v_2\ =\ 30i$

=> speed of first car,

$u_1\ =\ \sqrt{(20)^2+(25)^2}$

$=\ \sqrt{400+625}$

$=\ \sqrt{1025}$

= 32.01 units

and speed of second car,

$u_2\ =\ \sqrt{(30)^2+(0)^2}$

= 30 units

$u_2\ -\ u_1\ =\ 32.01\ -30$

= 2.01 units

Hence, 2nd car is running faster than the first car by 2.01 units.

8 0

2 years ago

How do i calculate this? PV = 100,000(1+0.03)

meriva

Answer:

103,000

Step-by-step explanation:

Use your knowledge of decimal arithmetic. Or, use a calculator.

100,000(1 +.03) = 100,000·1.03 = 1000·103 = 103,000

5 0

2 years ago

Does (40,0) make the equation y=0 true?

Basile [38]

Use the substitution method for y=0

(40,0)

y=0

0=0

Answer: (40,0) It does make the equation y=0 true

5 0

2 years ago

Read 2 more answers

I need to know the answer to 1,847,304,738 divided by 3

schepotkina [342]

Answer:

615,768,246

Step-by-step explanation:

If u divide 1847304738÷3 you get that.

3 0

2 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

2 years ago