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2 years ago

Help please im struggling.

Mathematics

2 answers:

murzikaleks [220]2 years ago

5 0

Answer:

Step-by-step explanation:

from the top one (Point A), to the bottom one (Point B) you go down 12 and to the right 8.

Hunter-Best [27]2 years ago

4 0

Answer:

D. 2,2

Step-by-step explanation:

The midpoint just means the point in the middle of the line, and if you count inwards from each of the points, you'll find that D is the midpoint.

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Evaluate if a = 6, b = 2, c = 9, & d = 3

bixtya [17]

Answer:

Step-by-step explanation:

a2 b

( )2 ( )

(–2)2 (3)

(4)(3)

7 0

3 years ago

is vector v with an initial point of (-5,22) and a terminal point of (20,60) equal to vector u with an intintal point of (50,120

marta [7]

Answer:

Yes, vectors u and v are equal.

Step-by-step explanation:

We need to check whether vectors u and v are equal or not.

If the initial point is $(x_1,y_1)$ and terminal point is $(x_2,y_2)$ , then the vector is

$Vector=(x_2-x_1)i+(y_2-y_1)j$

Vector v with an initial point of (-5,22) and a terminal point of (20,60).

$\overrightarrow v=(20-(-5))i+(60-22)j$

$\overrightarrow v=25i+38j$ ..... (1)

Vector u with an initial point of (50,120) and a terminal point of (75,158).

$\overrightarrow u=(75-50)i+(158-120)j$

$\overrightarrow u=25i+38j$ .... (2)

From (1) and (2) we get

$\overrightarrow u=\overrightarrow v$

Therefore, vectors u and v are equal.

5 0

3 years ago

While at the music store Drew bought five CDs all at the same price. The tax on his purchase was six dollars and the total was $

Natalka [10]

Answer:

Step-by-step explanation:

61- 6= 55 55÷5= 11 dollara for each cd

8 0

3 years ago

A bag contains five white balls and five black balls. Your goal is to draw two black balls.

umka21 [38]

Answer:

a.) the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b.) Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

Step-by-step explanation:

a) two balls are drawn at random .

total number of balls = 10

number of black balls = 5

number of white balls = 5.

the number of ways two balls can be drawn = $\binom{10}{2} = \frac{10!}{2! 8!} = \frac{10\times9}{2} = 45$

the number of ways two black balls can be drawn = $\binom{5}{2} = \frac{5!}{2! 3!} = \frac{5\times4}{2} = 10$

the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b) probability that First draw of two black balls = $\frac{2}{9}$

probability that first draw is of two white balls is and second draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9}$

Probability that first two draws are of white balls and the third draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9} \times\frac{2}{9}$

This is a geometric sequence and the final probability will be the sum of

all such probabilities, where we can take the the sequence to be an infinite series and the first term is $\frac{2}{9}$ and the common ratio is $\frac{2}{9}$ which is less than 1.

Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

3 0

3 years ago

8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member

tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

So the number of ways a committee of 5 students can be chosen from a student council of 30 students= $^{30}C_5=\dfrac{30!}{5!(30-5)!}$

$=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506$

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

4 0

3 years ago