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3 years ago

8

The two jar are geometrically similar.The height are 25cm and 10cm.The diameter of the larger jar is 7.5cm.Find the diameter of

the smaller jar.

1 answer:

In-s [12.5K]3 years ago

7 0

25/10 = 7.5/x

75/25x

x=75/25 = 3

diameter of smaller jar = 3 cm

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3 0

3 years ago

Read 2 more answers

babymother [125]

It is a valid sample because the first eight people were selected to participate? (the first one)

5 0

3 years ago

Read 2 more answers

Please help i am stuck and trying not to fail lol. also if you can show work pls

wel

Given:

The figure of rectangle.

To find:

a. The diagonal of the rectangle.

b. The area of the rectangle.

c. perimeter of the rectangle.

Solution:

(a)

In a right angle triangle,

$\sin \theta=\dfrac{Perpendicular}{Hypotenuse}$

$\sin 30=\dfrac{12}{Hypotenuse}$

$\dfrac{1}{2}=\dfrac{12}{Hypotenuse}$

$Hypotenuse=12\times 2$

$Hypotenuse=24$

So, the diagonal of the of the rectangle is 24 units.

(b)

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

$\tan 30=\dfrac{12}{Base}$

$\dfrac{1}{\sqrt{3}}=\dfrac{12}{Base}$

$Base=12\sqrt{3}$

Length of the rectangle is 12 and width of the rectangle is $12\sqrt{3}$ . So, the area of the rectangle is:

$Area=length \times width$

$Area=12 \times 12\sqrt{3}$

$Area=144\sqrt{3}$

So, the area of the rectangle is $144\sqrt{3}$ sq. units.

(c)

Perimeter of the rectangle is:

$P=2(length+width)$

$P=2(12+12\sqrt{3})$

$P=24+24\sqrt{3}$

$P\approx 65.57$

Therefore, the perimeter of the rectangle is about 65.57 units.

4 0

3 years ago