Question

Find the tangent of ∠I.

Answer 1

Answer:

tanI = $\frac{\sqrt{70} }{5}$

Step-by-step explanation:

We require to calculate GH using Pythagoras' identity in the right triangle.

GH² + GI² = HI²

GH² + 5² = ($\sqrt{95}$ )²

GH² + 25 = 95 ( subtract 25 from both sides )

GH² = 70 ( take square root of both sides )

GH = $\sqrt{70}$

Then

tanI = $\frac{opposite}{adjacent}$ = $\frac{GH}{GI}$ = $\frac{\sqrt{70} }{5}$