I believe the answer is true! good luck :)
The vertical distance between the roofs of the two buildings is 150 meters. Let’s use the equation below to determine the time required for the bag to drop 150 meters.
d = vi * t + ½ * 9.8 * t^2, d = 150 m
Since the bag is thrown horizontally, the initial vertical velocity is 0 m/s.
150 = ½ * 9.8 * t^2, t = √(150/4.9) ≈ 5.53 seconds
We can use the time to determine the minimum horizontal velocity required for the bag to travel 20 meters.
v = 20 ÷ √(150/4.9) ≈ 3.61 m/s
Since this velocity is less than 5 m/s. I believe that the bag to accused could throw the bag to the accomplice. I would advise the prosecuting attorney to do some pleas bargaining to get the accused the best deal possible. The accused is GUILTY!
The army
Hope it is correct!
Answer:
I'm pretty sure it's cross-section shape
Answer:
D) Anti-Prostitution Unit
Explanation:
a department or division of a police force that enforces laws against prostitution, drug abuse, illegal gambling, etc.
