We have been given that the quadratic equation models the path of a heavy ball through the air, where y represents the height in feet and x represents time in seconds. We are asked to find the time when ball will hit the ground.
The ball will hit the ground, when height of ball above ground will be 0. So we will equate our given quadratic equation with 0 and solve for x.
We will use quadratic formula to solve our given problem.
, where
b = Coefficient of x term,
a = Coefficient of term,
c = Constant.
Since time cannot be negative, therefore, the ball will hit the ground after 10 seconds.
Answer:
x = 4
Step-by-step explanation:
By looking at the graph we can see the vertical asymptote is the vertical line in the graph. This line goes through x = 4, and no matter what y is, x equals 4, as shown. Therefore, the equation of the vertical asymptote is x = 4.
Hello.
We are solving -9.4 > 1.7x + 4.2.
First we need to swap sides:
Now we need to subtract 4.2 from both sides.
1.7x + 4.2 = -9.4
-4.2 . -4.2
Now let's combine -4.2 + 4.2 which is 0.
We get 1.7x < -9.4 - 4.2
Now let's divide both sides by 1.7
1.7x | -13.6
1.7 1.7
x < -13.6
1.7
So we just divided to get x < -8.
<h3>
Answer: $1,314.40</h3>
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Explanation:
Assuming there are 324 seats available for the 324 students, this means that 324*5.60 = 1,814.40 dollars is earned in revenue from ticket sales.
Let x be the cost of equipment, lighting, and costumes combined.
The expression 1814.40 - x represents the profit made. It's the amount of money left after the bills are paid, so to speak. Or you could say profit = revenue - cost.
The committee wants $500 remaining, so they want 1814.40 - x to be equal to 500.
Let's solve for x
1814.40 - x = 500
-x = 500-1814.40
-x = -1314.40
x = 1314.40
So if $1,314.40 is spent on equipment, lighting, and costumes combined, then the committee will have $500 left over. If they spend less on those items, then the profit is more than $500. This means that $1,314.40 is the most they can spend.