Answer:
The equation of plane is
Step-by-step explanation:
We have to find the equation of plane passing through the point (0,-1,1) and orthogonal to the planes
Thus, we can write:
We will evaluate:
![n = n_1\times n_2\\\\n = \left[\begin{array}{ccc}i&j&k\\3&4&-3\\-3&2&4\end{array}\right] \\\\n = i(16 + 6)-j(12-9) +k(6+12)\\n = 22i-3j+18k\\n =](https://tex.z-dn.net/?f=n%20%3D%20n_1%5Ctimes%20n_2%5C%5C%5C%5Cn%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C3%264%26-3%5C%5C-3%262%264%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5Cn%20%3D%20i%2816%20%2B%206%29-j%2812-9%29%20%2Bk%286%2B12%29%5C%5Cn%20%3D%2022i-3j%2B18k%5C%5Cn%20%3D%20%3C22%2C-3%2C18%3E)
The required plane passes through the point (0,-1,1)
Thus, the equation of plane is
is the required equation of the plane.
Answer: 32
Step-by-step explanation: hope this helps
Answer:
I think it's B
Step-by-step explanation:
Hi there!
First, let's find the slope of the two points using the slope formula (y2 - y1 / x2 - x1).
S = 4 - 2 / 3 - 5
S = 2 / -2
S = -1
Next, we'll plug in the slope and a point into point-slope form (y - y1 = s(x - x1)) in order to find an equation. I will show the work using both points, which will result in two different equations.
(2,5)
y - 5 = -1(x - 2)
y - 5 = -x + 2
y = -x + 7
(4,3)
y - 3 = -1(x - 4)
y - 3 = -x + 4
y = -x + 7
The two equations came out the same! Which is completely okay, and happens sometimes.
Hope this helps!! :)
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