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Artyom0805 [142]
2 years ago
5

1.Give one example of an input

Computers and Technology
1 answer:
Sedbober [7]2 years ago
3 0

Answer:

Input: Keyboard, mouse, microphone

Output: monitor, loudspeakers

Input & Output: Network devices, Hard disks, USB drives, touch screen

Explanation:

Input devices are anything which provides information for a computer to act upon. The most common examples for a computer are the keyboard and mouse/trackball.

Output devices are anything which convey information which a computer has acted upon. The most common examples for a computer are the monitor and printer.

<h3>be happy </h3>

<h3 />
You might be interested in
A. Requiring computer users to log off before leaving for lunch
GuDViN [60]

Answer:

Option A, B, and D.

Explanation:

In the above question, the some details of the question are missing that is the part of the question.

Information Security applies to the mechanisms and techniques built and maintained to secure print, computerized, or any other type of personal, secret and confidential information or records from unauthorized access, usage, exploitation, release, damage, manipulation, or disturbance.

So, the following are the option that is true about the scenario.

Other option is not true about the scenario because Option C the click fraud are not the part or protect from the information security and Option F is not considered to the following scenario.

7 0
4 years ago
a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv
Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that  cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]  </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em>    if (digit == limit) {</em>

<em>        ans += (sum == 0);</em>

<em>        return sum == 0;</em>

<em>    }</em>

<em>    // if summation at digit position complete, validate it with result[digit].</em>

<em>    if (widx == words.size()) {</em>

<em>        if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em>            if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em>                return false;</em>

<em>            c2i[result[digit]] = sum % 10;</em>

<em>            i2c[sum%10] = result[digit];</em>

<em>            bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em>            c2i.erase(result[digit]);</em>

<em>            i2c.erase(sum%10);</em>

<em>            ans += tmp;</em>

<em>            return tmp;</em>

<em>        } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em>            if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em>                return false;</em>

<em>            }</em>

<em>            return helper(words, result, digit+1, 0, sum/10);</em>

<em>        } else {</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

<em>    // if word[widx] length less than digit, ignore and go to next word</em>

<em>    if (digit >= words[widx].length()) {</em>

<em>        return helper(words, result, digit, widx+1, sum);</em>

<em>    }</em>

<em>    // if word[widx][digit] already mapped to a value</em>

<em>    if (c2i.count(words[widx][digit])) {</em>

<em>        if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em>            return false;</em>

<em>        return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em>    }</em>

<em>    // if word[widx][digit] not mapped to a value yet</em>

<em>    for (int i = 0; i < 10; i++) {</em>

<em>        if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em>        if (i2c.count(i)) continue;</em>

<em>        c2i[words[widx][digit]] = i;</em>

<em>        i2c[i] = words[widx][digit];</em>

<em>        bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em>        c2i.erase(words[widx][digit]);</em>

<em>        i2c.erase(i);</em>

<em>    }</em>

<em>    return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em>    limit = result.length();</em>

<em>    for (auto &w: words) </em>

<em>        if (w.length() > limit) </em>

<em>            return;</em>

<em>    for (auto&w:words) </em>

<em>        reverse(w.begin(), w.end());</em>

<em>    reverse(result.begin(), result.end());</em>

<em>    int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em>    ans = 0;</em>

<em>    vector<string> words={"GREEN" , "BLUE"} ;</em>

<em>    string result = "BLACK";</em>

<em>    isSolvable(words, result);</em>

<em>    cout << ans << "\n";</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0
2 years ago
Session Hijacking refers to the exploitation of a valid computer session where an attacker takes over a session between two comp
noname [10]

Answer:Weak session ID generation algorithm

Explanation: Session hijacking is the hacking by disguising as the authenticated user and illegally exploit the particular computer session. IP packets are invoked by the disguised attacker into the active session between the legal computer user. It is also called session key.

It gives the hacker to use the data and services of the computer in an unauthorized manner. It arises due to the session of communication are not secure and strong,key used for session is weak etc.

5 0
3 years ago
Implement a function named largerThanN that accepts three arguments: an array of type int, the size of the array of type int and
levacccp [35]

Answer:

import java.util.Scanner;

public class NewArray {

//Main Method begins here

   public static void main(String[] args) {

   int [] numbers = {30,20,50,2,-1,44,3,12,90,32}; //The given array

   Scanner in = new Scanner(System.in);

       System.out.println("enter a number");

       int n = in.nextInt(); //Receive the number from the user

       //Calling the method largerThanN

       largerThanN(numbers, numbers.length,n);

   }

//The method largerThanN begins here

   public static void largerThanN(int []intArray, int arraySize, int n){

       for(int i = 0; i < intArray.length; i++){

           if(intArray[i] > n){

               System.out.println(intArray[i]);

           }

       }

   }

}

Explanation:

Uisng the Java prograamming language the solution is provided above.

Please see the comments within the code for detailed explanation

The key logic within the method largerThanN () is using a for loop to iterate the entire array. Within the for loop use an if statement to compare each element with the the number n entered by the user

6 0
3 years ago
What does OSS mean? ??
Viefleur [7K]
Ooeration support system. OSS is IT for running a communications network.
6 0
3 years ago
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