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White raven [17]
3 years ago
12

Help!!! ( i-ready math )

Mathematics
2 answers:
Ber [7]3 years ago
5 0

All Ages:- 9, 13, 9, 10, 10, 9, 10, 10, 11, 9

No. of ages = 10

\therefore Mean = \frac{9 + 13 + 9 + 10 + 10 + 9 + 10 + 10 + 11 + 9}{10}  \\  \\  =  \frac{100}{10}  \\  \\  = \bold{10}

\therefore Mean of all Ages = 10 years

<h3>Hope This Helps</h3>
kotykmax [81]3 years ago
4 0

Answer: 10

Step-by-step explanation:

Sum/Amount = 100/10 = 10

Brainliest?

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sineoko [7]

Answer/Step-by-step explanation:

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8. (4x² + 7x - 4) + (x² - 7x + 14)

Distribute +1 to each term in the parentheses by your right.

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Collect like terms and add together

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9. (2x³ + 6x² - 5x) + (x⁵ + 3x² + 8x + 4)

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Collect like terms and add together

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Rewrite in standard form

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10. (-6x⁵ - 2x + 13) + (4x⁵ + 3x² + x - 9)

-6x⁵ - 2x + 13 + 4x⁵ + 3x² + x - 9

Collect like terms

-6x⁵ + 4x⁵ - 2x + x + 13 - 9 + 3x²

Add like terms

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11. (5x² + 7x + 2) - (3x² + 6x + 2)

Distribute -1 to each term in the parentheses by your right.

5x² + 7x + 2 - 3x² - 6x - 2

Collect like terms

5x² - 3x² + 7x - 6x + 2 - 2

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12. (10x⁴ + 2x² + 1) - (3x⁴ + 3x + 11)

Distribute -1 to each term in the parentheses by your right.

10x⁴ + 2x² + 1 - 3x⁴ - 3x - 11

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Distribute -1 to each term in the parentheses by your right.

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8 0
3 years ago
3) 14 pennies to 35 pennies​
Leno4ka [110]

Answer:

<h2>2/5</h2>

Step-by-step explanation:

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Divide both the numerator and denominator by the GCD

14 ÷ 7

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I'm always happy to help :)

5 0
3 years ago
A researcher wishes to​ estimate, with 99​% ​confidence, the population proportion of adults who think the president of their co
scoray [572]

Answer:

a. n=4148

b. n=3909

c. The sample size is smaller if a known proportion from prior study is used. The difference in sample sizes is 239

Step-by-step explanation:

a. For sample where no preliminary estimate is given, the minimum sample size is calculated using the formula:

n=p(1-p)(\frac{z}{ME})^2

Where:

  • ME=Margin of error
  • p= is the assumed proportion

#Let p=0.5, substitute in the formula to solve for n:

n=0.5(1-0.5)\times (2.576/0.02)^2\\\\=4147.36\approx 4148

Hence, the minimum sample size is 4148

b. If given a preliminary estimate p=0.38, we use the same formula but substitute p with the given value:

n=p(1-p)(z/ME)^2\\\\=0.38(1-0.38)(2.576/0.02)^2\\\\=3908.47\approx3909

Hence, the minimum sample size is 3909

c. Comparing the sample sizes from a and b:

n_{0.5}>n_{0.38}\\\\n_{0.5}-n_{0.38}=4148-3909=239

Hence, the actual sample size is smaller for a known proportion from prior a prior study.

8 0
4 years ago
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