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Kamila [148]
2 years ago
11

Three circles are placed in a rectangle with width 12 cm, as shown below. Find the area of the shaded region. Use the value 3.14

for pi, and do not round your answer.
Mathematics
1 answer:
azamat2 years ago
7 0

Answer: area of rectangle

7x(7x2x3)

=294

area of 3 semicircles

7x2x3.14x0.5x3

=65.94

Answer

294-65.94

=228.06cm2

Step-by-step explanation:

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Solve????????????????????
seropon [69]

Answer:

10/49

Step-by-step explanation:

5*4 = 20

14*7 = 98

lowest term = 10/49

8 0
3 years ago
Calculate the AREA of the shape below. Give your answer in cm²
spayn [35]

Answer:

  • \boxed{\bf 26\:  cm^2}

Step-by-step explanation:

We got two shapes in the given figure,on the right we got a rectangle and on the left we have a square.

<u>Area of rectangle:-</u>

  • \bf 5 \times 2
  • \bf 10 \:cm^{2}

<u>Area of square :-</u>

  • \bf 4 \times 4
  • \bf 16 \: {cm}^{2}

<u>Total area :-</u>

  • \bf 10 + 16
  • \boxed{\bf 26 \: {cm}^{2} }
<h3><u>_________________________</u></h3>
5 0
3 years ago
Read 2 more answers
A helicopter hovers 1450 feet above a small island. The figure shows that the angle of depression from the helicopter to point P
puteri [66]

Answer:

1668 feet.

Step-by-step explanation:

We know the opposite side of the right triangle and we need the adjacent side, so we use the tangent function.

If the distance required is x  (adj side) we have:

tan 41 = opp/adj

tan 41 = 1450/x

x = 1450 / tan 41

= 1668.03

5 0
3 years ago
What is -3(4x-2)-2x ?
Margarita [4]

Step-by-step explanation:

- 3(4x - 2) - 2x \\  \\  =  - 12x + 6 - 2x \\  \\  =  - 14x + 6

7 0
4 years ago
I'm doing a task which involves magic v's, a maths pattern which has the rule of having the same total on each side. For e.g.
iogann1982 [59]

Answer:

--1-- (of set 23456)

2   4

5 3

 6

--2-- (of set 23456)

2   3

5 4

 6

--3-- (of set 23456)

2   5

6 3

 4

--4-- (of set 23456)

2   3

6 5

 4

--5-- (of set 23456)

3   5

4 2

 6

--6-- (of set 23456)

3   2

4 5

 6

--7-- (of set 23456)

3   6

5 2

 4

--8-- (of set 23456)

3   2

5 6

 4

--9-- (of set 23456)

3   5

6 4

 2

--10-- (of set 23456)

3   4

6 5

 2

--11-- (of set 23456)

4   5

3 2

 6

--12-- (of set 23456)

4   2

3 5

 6

--13-- (of set 23456)

4   6

5 3

 2

--14-- (of set 23456)

4   3

5 6

 2

--15-- (of set 23456)

5   4

2 3

 6

--16-- (of set 23456)

5   3

2 4

 6

--17-- (of set 23456)

5   6

3 2

 4

--18-- (of set 23456)

5   2

3 6

 4

--19-- (of set 23456)

5   6

4 3

 2

--20-- (of set 23456)

5   3

4 6

 2

--21-- (of set 23456)

6   5

2 3

 4

--22-- (of set 23456)

6   3

2 5

 4

--23-- (of set 23456)

6   5

3 4

 2

--24-- (of set 23456)

6   4

3 5

 2

--1-- (of set 34567)

3   5

6 4

 7

--2-- (of set 34567)

3   4

6 5

 7

--3-- (of set 34567)

3   6

7 4

 5

--4-- (of set 34567)

3   4

7 6

 5

--5-- (of set 34567)

4   6

5 3

 7

--6-- (of set 34567)

4   3

5 6

 7

--7-- (of set 34567)

4   7

6 3

 5

--8-- (of set 34567)

4   3

6 7

 5

--9-- (of set 34567)

4   6

7 5

 3

--10-- (of set 34567)

4   5

7 6

 3

--11-- (of set 34567)

5   6

4 3

 7

--12-- (of set 34567)

5   3

4 6

 7

--13-- (of set 34567)

5   7

6 4

 3

--14-- (of set 34567)

5   4

6 7

 3

--15-- (of set 34567)

6   5

3 4

 7

--16-- (of set 34567)

6   4

3 5

 7

--17-- (of set 34567)

6   7

4 3

 5

--18-- (of set 34567)

6   3

4 7

 5

--19-- (of set 34567)

6   7

5 4

 3

--20-- (of set 34567)

6   4

5 7

 3

--21-- (of set 34567)

7   6

3 4

 5

--22-- (of set 34567)

7   4

3 6

 5

--23-- (of set 34567)

7   6

4 5

 3

--24-- (of set 34567)

7   5

4 6

 3

Step-by-step explanation:

This javascript code is extremely brute-force, but it does the job:

function checkIfInSet(i, set) {

   return i.toString().split('').sort().join('') === set;

}

function checkIfMagic(s) {

   return (parseInt(s[0]) + parseInt(s[1]) == parseInt(s[3]) + parseInt(s[4]))

}

function printMagic(s) {

   console.log(`${s[0]}   ${s[4]}`);

   console.log(` ${s[1]} ${s[3]}`);

   console.log(`  ${s[2]}\n`);

}

function checkSet(set) {

   let counter = 1;

   for(let i=1; i<99999; i++) {

       if (checkIfInSet(i, set) && checkIfMagic(i.toString())) {

           console.log(`--${counter++}-- (of set ${set})`);

           printMagic(i.toString());

       }

   }

}

checkSet('23456');

checkSet('34567');

6 0
3 years ago
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