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2 years ago

Given sin 0 and angle 0 is in Quadrant II, what is the exact value of cos 0 in

Mathematics

1 answer:

Anna007 [38]2 years ago

4 0

sin = 3/7

1 = sin²0 + cos²0

cos²0 = 1 - 9/49

cos²0 = 40/49

cos0 = √(40) / 7

since its in Quadrant 2 the sin is positive and cos is negative

cos0 = - √(40) / 7

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Rewrite using a single exponent.<br> 53.53

Helga [31]

Answer:

${5}^{6} \: \: or \: \: {25}^{3} = 15625$

Step-by-step explanation:

${5}^{3} \times {5}^{3}$

Here we can solve this in 2 ways ,

Method 1 :

${5}^{3} \times {5}^{3}$

Here the bases are equal. So,

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Method 2 :

${5}^{3} \times {5}^{3}$

Here the exponents are same. So,

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sleet_krkn [62]

For this case we have the following system of equations:

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We solve by the substitution method:

We substitute the first equation in the second equation:

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We apply distributive property considering that $- * - = +:$

$-4x + 12x + 69 = 13\\8x + 69 = 13$

We subtract 69 from both sides of the equation:

$8x = 13-69\\8x = -56$

We divide by 8 on both sides of the equation:

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We look for the value of the variable y:

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Thus, the solution of the system is $(x, y): (-7,5)$

Answer:

$(x, y): (-7,5)$

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Step-by-step explanation:

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Ostrovityanka [42]

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Step-by-step explanation:

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