Answer:
(2,0)
Step-by-step explanation:
Simply plug in the coordinates. y= 3x - 6, so in this case 0= 3(2) - 6 or 0=0, making the point on the line. If the equation is not true like when using (0,3) and getting 3= -6, then the point is not on the line.
She would make 3.00 dollars
50(10) - 20(10) = (10)(50 - 20)
500 - 200 = (10 * 30)
300 = 300
(10)(50 - 20) = 30(10)
(10 * 30) = 300
300 = 300
Answers
9(x + y)
(7 - a)(b)
The Distributive Property is used in algebraic expressions to multiply a
single term and two or more terms which are inside a set of parentheses.
In the case of x(2y), there is only
one term inside the parenthesis
In the case of 9(x ∙ y), the distributive
property is not used because (x ∙ y) = xy which means only one term will be
multiplied by the term outside the parenthesis (9)
In the case of 9(x + y), the distributive
property is used because the two terms in the parenthesis (x and y) will be
multiplied by the term outside the parenthesis (9)
9(x + y) = 9*x + 9*y (by applying the distributive property)
In the case of (7 ∙ a)(b), the distributive
property is not used because (7 ∙ a) = 7a which means only one term will be
multiplied by the term outside the parenthesis (b)
In the case of (7 - a)(b), the distributive
property is used because the two terms in the parenthesis (7 and -a) will be
multiplied by the term outside the parenthesis (b)
(7 - a)(b) = 7*b - a*b (by applying the distributive
property)
In the case of (2 ∙ x) ∙ y, the distributive
property is not used because (2 ∙ x) = 2x which means only one term will be
multiplied by the term outside the parenthesis (y)
Answer:
(a,b)
Step-by-step explanation:
simply we find the midpoint of AC and the midpoint of Bd by dividing over 2
Answer: The volume of the tetrahedron is 2 units.
Step-by-step explanation:
Let A = (1, 1, 1)
B = (1, 5, 5)
C = (2, 2, 1)
The volume of a tetrahedron is given as
V = (1/6)|AB, AC, AD|
Where |AB, AC, AD| is the determinant of the matrix of AB, AC, AD.
We need to determine AB, AC, and AD
Suppose A = (a1, a2, a3)
B = (b1, b2, b3)
C = ( c1, c2, c3)
AB = ( b1 - a1, b2 - a2, b3 - a3)
Similarly for AB, AC, BC, etc.
AB = (1 - 1, 5 - 1, 5 - 1)
= (0, 4, 4)
AC = (1, 0, 2)
AD = (1, 1, 0)
Volume =
(1/6) |0 4 4|
|1 0 2|
|1 1 0|
= (1/6)[0(0 - 2) - 4(0 - 2) + 4(1 - 0)
= (1/6)(0 + 8 - 4)
= (1/6)(12)
V = 12/6 = 2 units
