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Virty [35]
2 years ago
14

Given sin 0 and angle 0 is in Quadrant II, what is the exact value of cos 0 in

Mathematics
1 answer:
Anna007 [38]2 years ago
4 0

sin = 3/7

1 = sin²0 + cos²0

cos²0 = 1 - 9/49

cos²0 = 40/49

cos0 = √(40) / 7

since its in Quadrant 2 the sin is positive and cos is negative

cos0 = - √(40) / 7

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Answer:

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Step-by-step explanation:

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77julia77 [94]

Based on the given problem of -7x⁴ = 36, the solution to the equation is x = -1.5.

<h3>What is the solution to this problem?</h3>

The equation to find x is given as:

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Step-by-step explanation:

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