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pochemuha
2 years ago
5

(3x10^(-15)) × (3x10^(3))

Mathematics
2 answers:
natima [27]2 years ago
5 0

Answer: 9e- 12

Step-by-step explanation:

mote1985 [20]2 years ago
3 0

Answer:

(3 \times 10)^{ - 12}  =  \frac{1}{(3 \times 10)^{12} }

Step-by-step explanation:

When we multiply two equal values with different power, we sum the two powers.

Negative power is equ to 1 over the value with positive power:

(3 \times 10)^{ - 15}  \times (3 \times 10) ^{3}  =  \\ (3 \times 10) ^{ - 15 + 3}  = (3 \times 10) ^{ - 12}  =  \\  =  \frac{1}{ {(3 \times 10)}^{12} }

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What is the goal of a proof by contradiction?
kifflom [539]

Answer:

B. The contradiction of the statement is proven false, so the original

statement is therefore proven true.

Step-by-step explanation:

We assume the opposite and then get to a point where we get a false statement.   That proves that the the opposite of the opposite ( what we originally wanted to prove) is true.

6 0
3 years ago
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-3/8 - 7/8 = <br>explicar el procedimiento por favor ​
pogonyaev

Answer:

-1/4

Step-by-step explanation:

-3/8 - 7/8= 4/8=1/2

4 0
3 years ago
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ArbitrLikvidat [17]

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4 0
4 years ago
A(a-bx)/x=2/3<br> PLEASE
RSB [31]

Answer:

This cannot be solved but it can be simplified

first we open the bracket

so we have

a²- abx/x = 2/3

next we cross multiply so it will be 3(a² - abx) = 2x

we get

3a² - 3abx = 2x

Next we factorise so we can get

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7 0
3 years ago
Given: △ACM, m∠C=90°, CP ⊥ AM
larisa86 [58]

Answer:  The answer is 3\dfrac{4}{7}.

Step-by-step explanation:  Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.

Now,

AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)

Comparing equations (A) and (B), we have

5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.

Thus,

AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.

8 0
4 years ago
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