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Alisiya [41]
2 years ago
6

What is the slope of the line graphed below? A) -5/2 B) 5/2 C) -2/5 D) 2/5

Mathematics
1 answer:
Oxana [17]2 years ago
6 0
C) -2/5, the slope is negative because your rise goes downward, and you always put rise over run so its -2/5 instead of -5/2
You might be interested in
2.1 , - 6/10 , -9/4 , -0.75 , 5/3 , least to greatest
WINSTONCH [101]

Answer:

-9/4, -0.75, -6/10, 5/3, 2.1

Step-by-step explanation:

This is a lot easier to figure out if you simplify the fractions and then change them to decimals

So -9/4 = -2 1/4 or -2.25

-0.75

-6/10 = -0.60

5/3 = 1 2/3 or 1.67

2.1

When you are ordering negatives, the biggest negative is the least. That is why -9/4 (-2.25) is the least number out of the five given.

The next one would be -0.75, because it is the second biggest negative fraction.

The next one is -0.60 because that is the 3rd biggest negative fraction (or the smallest because this is the last negative)

Now, because we're in the positives we start with 1.67, because it is smaller than the other number.

2.1 is our last number, so it is the greatest!

I hope this helped :)

6 0
3 years ago
A calculator which is marked at $120 is sold for cash at a 30% discount. How much change would Susan receive if she pays for the
solong [7]

Answer:

64 dollars

Step-by-step explanation: 120×30%= $36-$100= <u>$64</u>

5 0
2 years ago
Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

If k = 0, then this probability is equal to P(X1 = 1) = np(1-p)ⁿ¹⁻¹

If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

4 0
3 years ago
14 divided by 3 (27-11) x 3
stira [4]

14 ÷3 (27-11) x 3 = 224

4 0
3 years ago
5 + (-3) what is the answer
prohojiy [21]

5-3 is 2 the answer is 2

6 0
3 years ago
Read 2 more answers
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