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Alisiya [41]
3 years ago
6

What is the slope of the line graphed below? A) -5/2 B) 5/2 C) -2/5 D) 2/5

Mathematics
1 answer:
Oxana [17]3 years ago
6 0
C) -2/5, the slope is negative because your rise goes downward, and you always put rise over run so its -2/5 instead of -5/2
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harkovskaia [24]

Answer:

○\displaystyle -\frac{2\sqrt{3}}{3}\:[or\:-\frac{2}{\sqrt{3}}]

Step-by-step explanation:

You have to know the Unit Circle on this one. So, to start off, in the degree-angle range from 180° - 270° [Quadrant III], you must figure out the cosine value that gives you −½, and according to the graph, <em>theta</em><em> </em>will be represented as 240°. So, now that we have our <em>θ</em>, looking at the <em>y-value</em><em> </em>240°, since we want the <em>cosecant</em><em> </em>function, all we have to do is take the multiplicative inverse of \displaystyle -\frac{\sqrt{3}}{2},which gives you \displaystyle -\frac{2\sqrt{3}}{3}.

Extended Information

\displaystyle y-coordinate → sin\:θ \\ x-coordinate → cos\:θ

\displaystyle -\frac{2\sqrt{3}}{3} = [-\frac{\sqrt{3}}{2}]^{-1}

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