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expeople1 [14]
2 years ago
5

Let f(x)=x^{2}+18x+7\ and\ g(x)=-3x^{2}+2x-9.f(x)=x^2 +18x+7 and g(x)=−3x^2 +2x−9. Identify the solution(s) of f(x)=g(x).f(x)=g(

x).
Mathematics
1 answer:
brilliants [131]2 years ago
7 0

Answer:

x = -2

Step-by-step explanation:

f(x)=x^{2}+18x+7

g(x)=-3x^{2}+2x-9

f(x)=g(x)

\implies x^2 +18x+7=-3x^2 +2x-9

\implies 4x^2 +16x+16=0

\implies x^2 +4x+4=0

\implies (x+2)^2=0

\implies x+2=0

\implies x=-2

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3/2 g.oogle if you want the explanation of your work.

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3 years ago
a warehouse has 1,203 shirts to send 3 stores, If each store gets the same number of shirts , how many shirts will go to each st
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401 shirts

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1203 divided by 3 equals to 401

7 0
2 years ago
Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6
yan [13]
Each curve completes one loop over the interval 0\le t\le2\pi. Find the intersections of the curves within this interval.

6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi

The region of interest has an area given by the double integral

\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta

equivalent to the single integral

\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta

which evaluates to 9\pi+72.

8 0
3 years ago
A team is being formed that includes eight different people. There are eight different positions on the teams. How many differen
abruzzese [7]

Answer:

40320 different ways

Step-by-step explanation:

That problem is a permutation one

We have eight people to occupy  one position in a team, without any constraint at all

So

Total number of events   = P(8)

P (8)  =  8!

P (8)  =  8*7*6*5*4*3*2*1

P (8)  =  40320 different ways

6 0
3 years ago
If (3-4i) (x+iy) = 3 root 5<br> show that x^2 + y^2=9/5
NNADVOKAT [17]

Answer:

the answer is 2 + i.

Step-by-step explanation:

Let the square root of 3 + 4i be x + iy.

So (x + iy) (x +iy) = 3 +4i

=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i

=> x^2 – y^2 + 2xyi = 3 + 4i

Equate the real and complex terms

=> x^2 - y^2 = 3 and 2xy = 4

2xy = 4

=> xy = 2

=> x = 2/y

Substitute in

=> x^2 - y^2 = 3

=> 4/y^2 - y^2 = 3

=> 4 – y^4 = 3y^2

=> y^4 + 3y^2 – 4 = 0

=> y^4 + 4y^2 – y^2 – 4 =0

=> y^2(y^2 + 4) – 1(y^2 + 4) =0

=> (y^2 – 1) (y^2 + 4) =0

Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.

Therefore y = 1 and x = 2/1 = 2

The required square root of 3 + 4i is 2 + i.

5 0
3 years ago
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