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frutty [35]
2 years ago
9

The average textbook weighs 56 oz (3.5 pounds). How much is that in grams?

Mathematics
2 answers:
kakasveta [241]2 years ago
8 0

Answer:

1,590.4 pretty sure that's it

irina [24]2 years ago
4 0
The answer is 1590.4 grams. You get that by doing 56x28.4 which equals 1590.4.
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Bas_tet [7]
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Step By Step Explanation:
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3 years ago
C equals 2 pi r​; Cequals62.8 ​(Circumference of a​ circle)
tatuchka [14]

Answer:

about 10

Step-by-step explanation:

62.8 = 2 pi r/2

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31.4/pi = pi r/pi

about 10 = r

3 0
3 years ago
How to break down 4/5 + 13/15 = 1 2/3
nalin [4]

Answer:

Step-by-step explanation:

The left hand side of the equation contains proper fractions while the right hand side of the equation contains mixed fraction. The mixed fraction can be changed to improper fraction. 1 2/3 becomes 5/3

To breakdown the left hand side of the equation, we would take lowest common factor of 5 and 15. It is 15

Considering 4/5, if 15 divides 5,the result is 3. Multiplying 3 by 4 gives 12. So it becomes

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Considering 13/15, if 15 divides 15,the result is 1, Multiplying 1 by 13 gives 13. So it becomes

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6 0
3 years ago
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What is the median?<br> 6 6 - 8<br> -7 -6 8 -8
Mashcka [7]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Maria wraps the gift she is taking to a friend’s birthday party. She doesn’t have much paper, so she does not overlap any of the
Elina [12.6K]

Answer:

Total paper required to wrap the gift without any overlaps: 2700\ cm^{2}

Step-by-step explanation:

Here, we need to find the total paper required without any sides overlapping to wrap the gift.

The gift is of <em>cuboid </em>type.

Given the following:

<em>Length </em>= 15 cm

<em>Width </em>= 30 cm

<em>Height </em>= 20 cm

Please refer to the attached figure.

We can infer that to find the paper required, we actually need to the find the<em> total surface area of the cuboid</em>.

Because the gift wrap will be done <em>on the faces of gift</em> (which is of cuboid shape).

Formula for Surface Area of <em>Cuboid:</em>

\text {Area = } 2 \times (\text{Length}\times \text{Width} + \text{Width}\times \text{Height} + \text{Length}\times \text{Height} )\\\\\Rightarrow 2 \times (15 \times 30 + 30 \times 20 + 15 \times  20)\\\Rightarrow 2 \times (450 + 600 + 300)\\\Rightarrow 2 \times (1350)\\\Rightarrow 2700 cm^{2}

Hence, total paper required to wrap the gift without any overlaps: 2700 cm^{2}

8 0
3 years ago
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