The factors of a polynomial function are the zeros of the function
It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
<h3>How to show why the x - 3 is a factor</h3>
The function is given as:
m(x) = x^3 - x^2 - 5x - 3
The factor is given as:
x - 3
Set the factor to 0
x - 3 = 0
Solve for x
x = 3
Substitute 3 for x in the function
m(3) = 3^3 - 3^2 - 5(3) - 3
Evaluate
m(3) =0
Since the value of m(3) is 0, then x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
Read more about factors at:
brainly.com/question/11579257
<h2>
Explanation:</h2><h2>
</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. Here you forgot to write the relation so I could help you providing my own relation.
Remember that for any relation, we have a set
that matches the the domain (also called the set of inputs) of the function and the set
that contains the range (also called the set of outputs).
Suppose our relation is:

So the x-values represents the set A and the y-values the set B. Therefore, by evaluating the x-values into our relation we get:

So in this context, the correct option is:
B) (-9,-8, -7, -6, -5}
Y= 3.4. If you divide 37.4 by 11 then y would equal 3.4. Check by multiplying 3.4 by 11
Answer:
Step-by-step explanation: