Answer:
a
Step-by-step explanation:
you have to find the hole volume of the other shapes.
Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
This is the graph for that
<h2>♪Answer : </h2>
»f(x) = 9(9 + x)(10)
subtitute x = 2 for f(x).
»f(5) = 9(9 + 5)(10)
»f(5) = 9(14)(10)
»f(5) = 1,260✅
