Answer:
Yes
Step-by-step explanation:
Answer:
- perimter of original rectangle = <u>17. 6 mm</u>
- side length of the enlarged rectangle = <u>23. 22 mm</u>
- perimeter of the enlarged rectangle = <u>95. 04 mm</u>
Step-by-step explanation:
<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>
- Length of original rectangle = 4.5 mm
- Width of original rectangle = 4.3 mm
<em>perimeter = 2 × ( length + width)</em>
= 2 × ( 4.5 + 4.3)
= 2 × 8.8
= 17. 6 mm
<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>
- Width of original rectangle = 4. 5 mm
- Width of enlarged rectangle = 24.3 mm
Enlargement factor = 24.3 / 4.5
= 5.4
- Length of original rectangle = 4.5 mm
- Enlargement factor = 5.4
Side length of enlarged rectangle
= original length × Enlargement factor
= 4.3 × 5.4
= 23. 22 mm
<u>PERIMTER OF ENLARGED RECTANGLE</u>
= 2 × ( enlarged ength + enlarged breadth)
= 2 × (23. 22 + 24. 3 )
= 95. 04 mm
Answer: 5/6
Step-by-step explanation: If you graph out the relation and you do rise/run. You get 5 for the rise and 6 for the run.
Hope this helps! Please mark me brainiest.
D is the only viable answer among these, as A, B, and C all contain two even integers which, by definition, have a greatest common factor of 2.
<em>Correction: </em>I was incorrect in saying that <em>all </em>even integers have a greatest common factor of 2; 2 is at least guaranteed to be <em>one of the common factors </em>in any group of even numbers, but these examples all have it as their <em>greatest </em>common factor as well.
Answer:
9
Step-by-step explanation:
