6. An 8-in, main line needs to be flushed. The length of pipeline to be flushed is 250 ft. How many minutes will it take

Question 8 of 10

Andru [333]

Answer:

Function

Please mark me as brainliest.

3 0

2 years ago

Read 2 more answers

Tilly begins a running program to train for a marathon. She starts by running 1 mile the first week and tripling the number of m

Nuetrik [128]

Answer:

The sequence is a function as for any value of n we can not get more than one different $A_n$ value.

Step-by-step explanation:

Tilly starts by running 1 mile in the first week and tripling the number of miles each week.

Now, the number of miles Tilly will run can be modeled by the sequence $A_n = 1 \times 3^{(n - 1)}$ , where n is the number of weeks since she began her program.

Therefore, in the second week she runs 3 miles, in the third week she runs 9 miles and so on.

Therefore, the sequence is a function as for any value of n we can not get more than one different $A_n$ value. (Answer)

8 0

3 years ago

Verify that -tan2x = (2tanx) / (sec^2x - 2)

sashaice [31]

Answer:

Below.

Step-by-step explanation:

- tan 2x = -2tanx / (1 - tan^2x)

Using the identity tan^2x = sec^2x - 1 and substituting for tan^2x:

- tan 2x = -2 tanx / (1 - (sec^2x - 1))

= 2 tanx / ( - 1(sec^2x + 2))

= 2 tan x / (sec^2 x - 2)

8 0

3 years ago

Jeff bicycles 126 miles at the rate of r mph. The same trip would have taken 2 hours longer if he had decreased his speed by 4 m

weqwewe [10]

Given Information:

Distance = 160 miles

Required Information:

Rate = r = ?

Answer:

Rate = r = 20 mph

Step-by-step explanation:

Recall that the rate is given by

Rate = distance/time

$r = \frac{d}{t} \\\\t = \frac{d}{r} \\\\t = \frac{160}{r} \\\\$

It is given that the same trip would have taken 2 hours longer if he had decreased his speed by 4 mph.

Mathematically,

$\frac{160}{(r-4)} = \frac{160}{r} + 2 \\\\$

Simplify the equation

$\frac{160}{(r-4)} - \frac{160}{r} = 2 \\\\\frac{160r - 160(r-4)}{r(r-4)} = 2 \\\\\frac{160r - 160r+640)}{r(r-4)} = 2 \\\\160r - 160r+640 = r(r-4) (2) \\\\640 = r(r-4) (2) \\\\640 = (r^2 - 4r) (2) \\\\640 = 2r^2 - 8r \\\\2r^2 - 8r-640 =0 \\\\2(r^2 - 4r-320) =0 \\\\r^2 - 4r-320 =0 \\\\$

Now we are left with a quadratic equation.

We may solve the quadratic equation using the factorization method

$r^2 - 4r-320 =0 \\\\r^2-20r+16r-320=0 \\\\r(r-20)+16(r-20)=0 \\\\(r-20) (r+16)=0 \\\\$

So,

$(r-20) = 0 \\\\r = 20 \\\\$

OR

$(r+16)=0 \\\\r = -16 \\\\$

Since rate cannot be negative, discard the negative value of r

Therefore, the rate is

$r = 20 \: mph$

3 0

4 years ago

A triangle ABC is inscribed in a circle, such that AB is a diameter. What are the measures of angles of this triangle if measure

Katen [24]

Answer:

∠C=90°

∠A=67°

∠B=23°

Step-by-step explanation:

For angle C:

Thales' Theorem states that an angle inscribed across a circle's diameter is always a right angle.

Therefore, since AB is the diameter(hypotenuse) then angle C is the right angle. (90°)

For Angle A:

The measure of arc BC= 134 degrees. We can just use a formula for an inscribed triangle. ∠A = 1/2 (mBC)

∠A= (1/2)134

∠A= 77°

For angle B:

All triangle angles all add up to 180. We can just subtract angles A and C from 180°:

∠B = 180-(90+67)

∠B = 23°

8 0

4 years ago