You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
Answer:
37.5
Step-by-step explanation:
split in the middle, 5×5=25/2=12.5
12.5= triangle
5×5=25
25=square
12.5+25=37.5
2/3 + 5/6
= 4/6 + 5/6
= 9/6
= 3/2
A. 3/2
Step-by-step explanation:
from the line above
P1 = -2
P2 = -1
P3 = 1/3
P4 = 2/3
P5 = 1 1/2 = 3/2
The product of P1 to P5,P
=> P = -2×-1×1/3×2/3×3/2 = 2/3
Answer:
x= - AB-4/5 and No Solution
False for all xER
Step-by-step explanation:
