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arsen [322]
2 years ago
13

Henrietta receives a Valentine’s card from a secret admirer. The admirer uses the codename ‘Ejctnkg’. Henrietta cracks the code

and replies using the name ‘Jgptkgvvs.’ What is her admirer’s name? Type your answer in below.
Spanish
2 answers:
Nana76 [90]2 years ago
8 0

The name of the admirer based on the code that was sent with the card was <u>Charlie</u>.

<h3>Decoding the code.</h3>

Based on Henrietta's message, we can infer that each letter in the code is the second letter from the person's name.

  • Second letter from H is J.
  • Second letter from E is G.
  • Second letter from n is p and so on.

The code would therefore be:

  • Second letter before E - C
  • Second letter before J - H
  • Second letter before C - A
  • Second letter before T - R
  • Second letter before N - L
  • Second letter before K - I
  • Second letter before G - E

In conclusion, this is Charlie.

Find out more on using codes at brainly.com/question/904077.

Zanzabum2 years ago
3 0
The admirers name is charlie the code is skipping a letter so a=c, b=d, c=e…
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