Henrietta receives a Valentine’s card from a secret admirer. The admirer uses the codename ‘Ejctnkg’. Henrietta cracks the code
and replies using the name ‘Jgptkgvvs.’ What is her admirer’s name? Type your answer in below.
2 answers:
The name of the admirer based on the code that was sent with the card was <u>Charlie</u>.
<h3>Decoding the code.</h3>
Based on Henrietta's message, we can infer that each letter in the code is the second letter from the person's name.
- Second letter from H is J.
- Second letter from E is G.
- Second letter from n is p and so on.
The code would therefore be:
- Second letter before E - C
- Second letter before J - H
- Second letter before C - A
- Second letter before T - R
- Second letter before N - L
- Second letter before K - I
- Second letter before G - E
In conclusion, this is Charlie.
Find out more on using codes at brainly.com/question/904077.
The admirers name is charlie the code is skipping a letter so a=c, b=d, c=e…
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