Henrietta receives a Valentine’s card from a secret admirer. The admirer uses the codename ‘Ejctnkg’. Henrietta cracks the code and replies using the name ‘Jgptkgvvs.’ What is her admirer’s name? Type your answer in below.
2 answers:
The name of the admirer based on the code that was sent with the card was <u>Charlie </u>.
<h3>Decoding the code.</h3>
Based on Henrietta's message, we can infer that each letter in the code is the second letter from the person's name.
Second letter from H is J. Second letter from E is G. Second letter from n is p and so on.
The code would therefore be:
Second letter before E - C Second letter before J - H Second letter before C - A Second letter before T - R Second letter before N - L Second letter before K - I Second letter before G - E
In conclusion, this is Charlie .
Find out more on using codes at brainly.com/question/904077 .
The admirers name is charlie the code is skipping a letter so a=c, b=d, c=e…
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