Answer:
100
Step-by-step explanation:
We assume that you are concerned with integers, and that you only count a number as "3-digit" if it does not have a zero in the hundreds place.
In order for the number to have a minimum value, the minimum available digit must be used in each number place, starting from the most-significant place--the hundreds place.
The least (non-zero digit) available for the hundreds place is 1.
The least digit available for the tens place is 0.
The least digit available for the ones place is also 0, since it is allowed to duplicate a digit already used.
The least possible 3-digit number using 2 different digits is 100.
Answer:
see below
Step-by-step explanation:
The ratio of terms that are two terms apart (s4 and s6) is the square of the common ratio:
s6/s4 = r^2
r = √(8/18)
r = 2/3 . . . . . matches choices A and C
__
Using the formula for the general term, we now know enough to find the first term:
sn = s1·r^(n-1)
s4 = s1·(2/3)^(4-1)
Using s4 = 18 and multiplying by (2/3)^-3, we get ...
18·(2/3)^-3 = s1 = 18·27/8
s1 = 243/4 . . . . . matches choice A
<u>The concept:</u>
We are given the equation:
Which can be simplified as:
Since any number to the power '0' is 1
x² - x must be equal to 0 for the given equation to be true
<u></u>
<u>Solving for x:</u>
x² - x = 0
x(x-1) = 0
now, we can divide both sides by either x OR x-1
So we will see what we get for either choice:
x = 0/(x-1) x-1 = 0/x
x = 0 x = 1
Hence, the value of x is either 0 or 1