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lina2011 [118]
1 year ago
6

In one day, The Tool Shed rented out 25 self-propelled and riding mowers for a total fee of $900. The dolly rental cost was $20

for each self-propelled mower and $40 for each riding mower. Find the number of self-propelled mowers "(x)" and the number of riding mowers " (y)' rented for that day
Mathematics
1 answer:
masha68 [24]1 year ago
4 0

They rented out 5 self-propelled mowers and 20 riding mowers.

Data;

  • Total number of tool rented out = 25
  • Cost of tools rented = $900

<h3>System of Equations</h3>

To solve this problem, we have to write a system of equations to represent the problem.

since we have

  • x = self - propelled mower
  • y = riding mowers

Let's write equations with these variables.

x+y = 25...equation (i)\\20x+40y = 900...equation(ii)

From equation (i)

x+y= 25\\x = 25 - y...equation(iii)

Put equation (iii) into equation (ii)

20x+40y=900\\x = 25-y\\20(25-y)+40y=900\\\\500-20y+40y=900\\500+20y=900\\20y=900-500\\20y=400\\\frac{20y}{20}=\frac{400}{20}\\ y=20

Let's substitute the value of y into equation(i)

x+y =25\\x+20 = 25\\x = 25 - 20\\x = 5

From the calculations above, they rented 5 self-propelled mowers and 20 riding mowers.

Learn more on system of equations here;

brainly.com/question/13729904

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Answer:

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Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;

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<h2>          76 cm</h2>

Step-by-step explanation:

|FE| = |CB| = 4\cdot2=8\,cm\\\\|ED|=|DC|= \sqrt{(3\cdot2)^2+(4\cdot2)^2}= \sqrt{6^2+8^2}=\sqrt{100}=10\,cm\\\\|FA|=|AB|= \sqrt{(6\cdot2)^2+(8\cdot2)^2}= \sqrt{144+256}=\sqrt{400}=20\,cm\\\\\\Circumference = FE+ED+DC+CA+AB+FA\\\\Circumference =8+10+10+8+20+20=76\,cm

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