Question

If t = αx + βx² then find relation between velocity and acceleration.​

Answer 1

Explanation:

I hope this helps you bro!

Answer 2

Answer:

1st of all differentiate the eq with respect to time, you will get dx/dt i.e velocity.

dt/dt=d(ax^2)/dt+d(bx)/dt

or, 1=2ax(dx/dt)+b(dx/dt);

or,1=(2ax+b)dx/dt;

0r dx/dt=1/(2ax+b)

so, velocity v=dx/dt=(2ax+b)^-1

now, acceleration =dv/dt=-1(2ax+b)^-2(2a+0);

or dv/dt=-2a/(2ax+b)^2;

here acceleration is the function of x i.e position of the particle so acceleration will vary position to position