2 years ago

Does anyone know how to write an equation for two points of (0,-3) and (8,-5) PLEASE HELP

Mathematics

1 answer:

Aleksandr [31]2 years ago

6 0

0,-3 8,-5. if we are finding slope, it's x2-x1 y2-y1.

8-0=8. -5-(-3)=-5+3=8

8,8

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Need Help help me plz ;(

omeli [17]

So in order to solve you must first combine like terms.
-2y + 2y + 3 = 3
0 + 3 = 3
Subtract 3.
0 = 0
The answer is infinate solution because both numbers are the same.
I hope this helps love! :)

7 0

3 years ago

Given g(x)=8x+3 find the following g(-1) and g(2a+1)

Degger [83]

Answer:

g(-1) = -5

g(2a+1) = 16a+11

Step-by-step explanation:

Substitute the given value into the function and evaluate.

So for g(x) = 8x+3

You substitute g(-1)

So g(-1) = 8(-1)+3

That is how you get -5

Then g(2a+1)

So g(2a+1) = 8(2a+1)+3

Thats how you get 16a+11

Hope this helps. Mark as brainlist

4 0

3 years ago

PLZ HELP!!!!!!! will mark brainliest!!!!

alexgriva [62]

Answer:

it is many triangles

Step-by-step explanation:

6 0

4 years ago

*Simple math question* The eighth grade class at grade school has 15 girls and 14 boys. How many different boy-girl dates can be

AlladinOne [14]

15*14=210
210 boy-girl dates

3 0

3 years ago

Can anyone help me with this please

olga_2 [115]

Hi there!

$\large\boxed{\frac{1}{4}, -\frac{3}{2}}$

13y² + 10y - 3 = 5y²

Begin by moving all terms to one side:

13y² + 10y - 3 - 5y² = 0

Combine like terms:

8y² + 10y - 3 = 0

Factor using the guess-and-check method.

(4y - 1)(2y + 3) = 0

Set each factor equal to 0 to find the solutions:

4y - 1 = 0

4y = 1

y = 1/4

2y + 3 = 0

2y = -3

y = -3/2

8 0

3 years ago