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3 years ago

Three examples of front end estimation

Mathematics

2 answers:

lord [1]3 years ago

6 0

Answer:

In front-end estimation, we replace the original number with a number that's close by but only has one non-zero digit. For example, 20, 300, -50, 1,000, 80,000. Take the number 32; the choices to replace it with are 30 or 40 (they both have only one non-zero digit)

Step-by-step explanation:

BARSIC [14]3 years ago

5 0

Answer: 20, 300, -50, 1,000, 80,000. Take the number 32; the choices to replace it with are 30 or 40 (they both have only one non-zero digit).

Step-by-step explanation: In front-end estimation, we replace the original number with a number that's close by but only has one non-zero digit.

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find the constant m and b in the linear function f(x)=mx+b so that f(6)=9 and the straight line represents by f has slope -4

Charra [1.4K]

Answer:

The constant m=-4, and b=33

Step-by-step explanation:

F(x)= MX+b

If f(6)=9 then x=6, m= -4

9= -4(6) + b

9= -24 + b

b= 9 + 24

b= 33

Therefore the constant m, which is the slope is -4 and b which is the intercept is 33

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3 years ago

B) A shopkeeper sold her goods for Rs 16,950 allowing 25 % discount and then levied on

Damm [24]

Answer:

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3 years ago

How can you generate x-3y+5 from the expression x+y+4+2y+1

vladimir2022 [97]

Answer: Here is the explanation. also it it +3y not -3y

Step-by-step explanation:

x+y+4+2y+1=x+3y+5 because

2y+y=3y

so now you have x+3y+4+1

4+1=5

now you have: x+3y+5

if you do not understand, What i am trying to say is, you need to add all of the same things.

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3 years ago

If Trent has 11 quarters and dimes in his pocket, and they have a combined value of 200 cents, how many of each coin does he hav

allsm [11]

Answer:

Trent has 6 quarters and 5 dimes.

Step-by-step explanation:

Consider the provided information.

Let q = Number of quarters

d = Number of dimes.

Trent has 11 quarters and dimes.

$q+d=11$

$q=11-d$

The worth of a quarter is 25 cents.

The worth of a dimes is 10 cents

$25q+10d=200$

Substitute the value of q in above equation.

$25(11-d)+10d=200$

$275-25d+10d=200$

$15d=75$

$d=5$

Substitute the value of d in $q=11-d$

$q=11-5$

$q=6$

Hence, Trent has 6 quarters and 5 dimes.

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3 years ago

A circus audience sits in rows around the performing ring. There are 9 seats in each row. How many rows will need to be set up i

DENIUS [597]

Answer:

57 rows

Step-by-step explanation:

Since each row will have a total of 9 seats, then we would simply need to divide the total number of individuals that will attend the show by 9 in order to calculate the number of rows that need to be set up around the performing ring.

513 / 9 = 57 rows

Therefore, we can see that we would need a total of 57 rows of 9 chairs each in order for there to be enough chairs to seat 513 people.

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3 years ago