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lozanna [386]
3 years ago
13

Im just confused how to solve the length.​

Mathematics
2 answers:
Slav-nsk [51]3 years ago
3 0

Answer:

Ste

Random draws are often used to make a decision where no rational or fair basis exists for making a deterministic decision, or to make unpredictable moves.p-by-step explanation:

taurus [48]3 years ago
3 0

Answer:

  a) angle DEF = 75°

  b) DF = 21/4 cm = 5 1/4 cm

  c) BC = 20/3 cm = 6 2/3 cm

Step-by-step explanation:

I sometimes find it helpful to write down corresponding angles and sides:

Angles:

  • A and D
  • B and E (75°)
  • C and F

Sides:

  • AB (4 cm) and DE (3 cm)
  • BC (??) and EF (5 cm)
  • CA (7 cm) and FD (??)

__

The triangles are similar, so corresponding angles are congruent, and corresponding sides are proportional. This lets us write proportions for the missing side lengths:

  DF/CA = DE/AB

  DF = CA(DE/AB) = (7 cm)(3/4) = 21/4 cm

and

  BC/EF = AB/DE

  BC = EF(AB/DE) = (5 cm)(4/3) = 20/3 cm

_____

<em>Additional comment</em>

We have written the proportions so the unknown value is in the numerator of the fraction. That lets us solve it in a single step: multiply the equation by the denominator. This means the proportion in part (b) has the smaller length in the numerator, while the proportion in part (c) has the larger length in the numerator.

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Tammy has scored 82, 78, and 93 on her previous three tests. What score does she need on her next test so that her average (mean
Lyrx [107]

Answer:

She needs a grade of 71 on her next text.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the number of values.

Tammy has scored 82, 78, and 93 on her previous three tests.

Thus, her grades are 82, 78, 93 and x, in which x is her grade in the fourth test.

There are 4 tests.

What score does she need on her next test so that her average (mean) is 81?

We have to find x when the mean is 81. So

\frac{82 + 78 + 93 + x}{4} = 81

253 + x = 324

x = 324 - 253

x = 71

She needs a grade of 71 on her next text.

5 0
4 years ago
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WARRIOR [948]
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meriva
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Two lines, R and M, are represented by the following equations:
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4 years ago
A manufacturer of personal computers sets tests competing brands and finds that the amounts of energy they require are normally
jeyben [28]

Answer:

b. [278.90, 288.55]

See the explanation below.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the amounts of energy of a population, and for this case we know the distribution for X is given by:

X \sim N(285,9.1)  

Where \mu=285 and \sigma=9.1

LOWER LIMIT

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.75   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=285 -0.674*9.1=278.90

So the value of height that separates the bottom 25% of data from the top 75% is 278.90.  

UPPER LIMIT

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.3   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.7 of the area on the left and 0.3 of the area on the right it's z=0.524. On this case P(Z<0.524)=0.7 and P(z>0.524)=0.3

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.524

And if we solve for a we got

a=285 +0.524*9.1=289.78

So the value of height that separates the bottom 70% of data from the top 30% is 289.78.  

With the procedure we got for the limits [278.9 , 289.78]

And since any of the options are on the list we take th most similar for this case:

b. [278.90, 288.55]

4 0
4 years ago
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